A block of mass M hangs straight down from a string of length L. A ball of mass m and speed v0 hits the block. The ball attaches so that the block and ball swing out since as one body. a) Find the velocity of the joint immediately after the impact expressed in terms of m, M and v0. b) If the ball does
A block of mass M hangs straight down from a string of length L. A ball of mass m and speed v0 hits the block. The ball attaches so that the block and ball swing out since as one body. a) Find the velocity of the joint immediately after the impact expressed in terms of m, M and v0. b) If the ball does
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Author:Raymond A. Serway, Chris Vuille
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Chapter6: Momentum, Impulse, And Collisions
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A block of mass M hangs straight down from a string of length L. A ball of mass
m and speed v0 hits the block. The ball attaches so that the block and ball swing out
since as one body.
a) Find the velocity of the joint immediately after the impact expressed in terms of m, M and v0.
b) If the ball does not stick to the block, but ricochets straight back into a
perfectly elastic impact, calculate the speed of both ball and block immediately after the impact.
Calculate with m = 0.0050 kg, M = 10 kg and v0 = 100 m/s.
c) What was the average force on the block from the ball in it
elastic impact if the impact lasted for 0.0050 s?
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