Answer the missing parts For an inclined plane. The normal force isn=mgThen,Hs=mgcos(e)so:Hs=tan(0) A block of mass m is placed on a rough surface inclined relative to the horizontal. The incline angle is increased until the block start tomove. Show that you can obtain the coefficient of static friction us by measuring the critical angle 0 where slipping occurs.mySolutionJust before slipping, we say that the block is still at rest, so the net force on the x-axis is:EFx=mg-fEvaluating, we get:= mgBut the frictional force is expressed as the product of coefficient and the normal force so.Ps= mgFor an inclined plane. The normal force isn=mg

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A block of mass m is placed on a rough surface inclined relative to the horizontal. The incline angle is increased until the block start to move. Show that you can obtain the coefficient of static friction Ps by measuring the critical angle 0 where slipping occurs. to

A block of mass m is placed on a rough surface inclined relative to the horizontal. The incline angle is increased until the block start to move. Show that you can obtain the coefficient of static friction Ps by measuring the critical angle 0 where slipping occurs. to

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter6: Applications Of Newton's Laws

Section: Chapter Questions

Problem 123AP: Two blocks connected by a string are pulled across a horizontal surface by a force applied to one of...

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Torque

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Question

Answer the missing parts

For an inclined plane. The normal force is
n=mg
Then,
Hs=mg
cos(e)
so:
Hs=
tan(0)

A block of mass m is placed on a rough surface inclined relative to the horizontal. The incline angle is increased until the block start to
move. Show that you can obtain the coefficient of static friction us by measuring the critical angle 0 where slipping occurs.
my
Solution
Just before slipping, we say that the block is still at rest, so the net force on the x-axis is:
EFx=mg
-f
Evaluating, we get:
= mg
But the frictional force is expressed as the product of coefficient and the normal force so.
Ps
= mg
For an inclined plane. The normal force is
n=mg

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