Asked Dec 12, 2019

A block of mass 14.0 kg slides from rest down a frictionless 40.0° incline and is stopped by a strong spring with k = 2.30 ✕ 104 N/m.The block slides 3.00 m from the point of release to the point where it comes to rest against the spring. When the block comes to rest, how far has the spring been compressed?


Expert Answer

Step 1

According to energy conservation law, potential energy of block at the top of inc...


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PE = PE, PEgire spring mgh=kx mg (Isine) = kx² (14.0kg)(9.8m/s³)((3.00m)(sin 40.0°)) = ÷(2.30 × 10ʻN/m)x² 264.6kg - m² /s° =(5.75 × 10° N/m)x² x- 264.6kg m²/s? 5.75 × 10°N/m = 0.214m


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