A blue product absorbs light at 590 nm (ε590nm = 7,600 M-1 cm-1). Its concentration was too concentrated to determine an accurate absorbance reading. Therefore, the solution was diluted in the following manner before reading it's absorbance. 0.500 mL was added to 1.000 mL of water to make "Dilution 1". Then 0.700 mL of "Dilution 1" was added to 3.000 mL of water to make "Dilution 2". The absorbance reading of "Dilution 2" was determined to be 0.220 when using a 1 cm pathlength. Determine the millimolar (mM) concentration of the blue product in the enzyme reaction. Indicate the concentration to the precision of 3 decimal places. ANS: 0.078 nM. Would like some steps on how to get this answer.

Living by Chemistry
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ISBN:9781464142314
Author:Angelica M. Stacy
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ChapterU5: Fire: Energy , Thermodynamics, And Oxidation-reduction
SectionU5.116: How Absorbing: Spectroscopy
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A blue product absorbs light at 590 nm (ε590nm = 7,600 M-1 cm-1).

Its concentration was too concentrated to determine an accurate absorbance reading. Therefore, the solution was diluted in the following manner before reading it's absorbance.

0.500 mL was added to 1.000 mL of water to make "Dilution 1".

Then 0.700 mL of "Dilution 1" was added to 3.000 mL of water to make "Dilution 2".

The absorbance reading of "Dilution 2" was determined to be 0.220 when using a 1 cm pathlength.

Determine the millimolar (mM) concentration of the blue product in the enzyme reaction. Indicate the concentration to the precision of 3 decimal places.

ANS: 0.078 nM. Would like some steps on how to get this answer. Thanks.

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