O NY a. Draw the structure of the tetrahedral intermediate INITIALLY FORMED in the reaction shown. + . You do not have to consider stereochemistry. • Do not include counter-ions, e.g., Na+, I, in your answer. • In cases where there is more than one answer, just draw one. ***** 2 CH3CH2NH2 H3C KY ?
Reactive Intermediates
In chemistry, reactive intermediates are termed as short-lived, highly reactive atoms with high energy. They rapidly transform into stable particles during a chemical reaction. In specific cases, by means of matrix isolation and at low-temperature reactive intermediates can be isolated.
Hydride Shift
A hydride shift is a rearrangement of a hydrogen atom in a carbocation that occurs to make the molecule more stable. In organic chemistry, rearrangement of the carbocation is very easily seen. This rearrangement can be because of the movement of a carbocation to attain stability in the compound. Such structural reorganization movement is called a shift within molecules. After the shifting of carbocation over the different carbon then they form structural isomers of the previous existing molecule.
Vinylic Carbocation
A carbocation where the positive charge is on the alkene carbon is known as the vinyl carbocation or vinyl cation. The empirical formula for vinyl cation is C2H3+. In the vinyl carbocation, the positive charge is on the carbon atom with the double bond therefore it is sp hybridized. It is known to be a part of various reactions, for example, electrophilic addition of alkynes and solvolysis as well. It plays the role of a reactive intermediate in these reactions.
Cycloheptatrienyl Cation
It is an aromatic carbocation having a general formula, [C7 H7]+. It is also known as the aromatic tropylium ion. Its name is derived from the molecule tropine, which is a seven membered carbon atom ring. Cycloheptatriene or tropylidene was first synthesized from tropine.
Stability of Vinyl Carbocation
Carbocations are positively charged carbon atoms. It is also known as a carbonium ion.
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a. Draw the structure of the tetrahedral intermediate INITIALLY FORMED in the reaction shown.
• You do not have to consider stereochemistry.
• Do not include counter-ions, e.g., Na+, I, in your answer.
. In cases where there is more than one answer, just draw one.
90-85
+ 2 CH3CH2NH2
H3C.
H₂
4
[ ] در
?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb7006288-c34d-4b87-8c41-0af7c801069e%2Fa6010112-07cc-435b-b156-96d4a7814bbe%2F5qrwo5o_processed.jpeg&w=3840&q=75)
![b. Draw the structures of the final acyl transfer products obtained.
0
• You do not have to consider stereochemistry.
• Draw organic products only.
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• Draw the neutral form of the products; no charges.
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• Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner.
• Separate multiple products using the + sign from the drop-down menu.
9-85
****
?
ChemDoodle
[ ] در](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb7006288-c34d-4b87-8c41-0af7c801069e%2Fa6010112-07cc-435b-b156-96d4a7814bbe%2Fdv8brfp_processed.jpeg&w=3840&q=75)
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