A bob of mass m is suspended from point O by a massless string of length I as shown. At the bottommost point it is given a velocity u = √/12gl for 1 = 1m and m = 1kg, match the following two columns when string becomes horizontal (g = 10ms) List 1 Speed of bob Acceleration of bob 0. I List 2 10 20 U Tension in string Tangential acceleration of bob None 100

A bob of mass m is suspended from point O by a massless string of length I as shown. At the bottommost point it is given a velocity u = √/12gl for 1 = 1m and m = 1kg, match the following two columns when string becomes horizontal (g = 10ms) List 1 Speed of bob Acceleration of bob 0. I List 2 10 20 U Tension in string Tangential acceleration of bob None 100

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter9: Linear Momentum And Collisions

Section: Chapter Questions

Problem 9.1CYU: Check Your Understanding The U.S. Air Force uses “10gs” (an acceleration equal to 109.8m/s2 ) as the...

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