A Brinell hardness measurement of 650 HBN, using a 10-mm-diameter indenter and a 2950 kg load on an aluminum plate. Determine the indentation diameter. O a. 2.683 mm O b. 2.836 mm Oc.2.368 mm O d. 2.386 mm

A Brinell hardness measurement of 650 HBN, using a 10-mm-diameter indenter and a 2950 kg load on an aluminum plate. Determine the indentation diameter. O a. 2.683 mm O b. 2.836 mm Oc.2.368 mm O d. 2.386 mm

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Q: In the Brinell hardness test, if the load used 1200 kg, and the ball diameter 6 mm, write down the…

A: Given details: P=1200kgD=6mmBHN=586 formula used: BHN=2PπDD-D2-d2

Q: In the BrinelI hardness test, if the load used 1200 kg, and the ball diameter 6 mm, write down the…

Q: 2. Compute the tensile strength and ductility (%EL) of a cylindrical copper rod if it is cold worked…

Q: hardness

Q: A mild steel material is subjected to a Brinell hardness test with an applied force of 7459 N using…

A: Given: The applied force is F=7459 N, The indentor (steel ball) diameter is D=11 mm, Brinell…

Q: Compare between the hardness profile for the following cases, in the radial and longitudinal section…

A: Hardness - Longitudinal distance

Q: (a) Derive the value of Brinell hardness using a hard spherical indenter, which was developed by…

A: Solution: Note: Dear Student! As per our guidelines, we are only allowed to answer a single…

Q: i) The elongation of the specimen at load 80 kN (in mm) --

Q: In tensile testing a tensile load is applied to the specimen until it O a. bend O b. fractures O C.…

Q: The ability of a material to undergo large permanent deformation with the application of a tensile…

A: Elasticity: It is the ability of the material which allows to return to its original shape and size…

Q: Determine the indentation diameter and the surface area of indentation of a copper material…

A: Given: BHN = 955 D = 10 mm W = 9.4 kN Thus, F=Wg=9.4×1039.81=958.2 kg

Q: Required information A centric load P is applied to the granite block shown. The resulting maximum…

A: Calculated force P.

Q: 38)A tensile test specimen has a gage length=3.0 inches and a diameter= .75 inches. Yielding occurs…

A: Given data:Gauge length = 3 inchesDiameter d = 0.75 inchesLoad at yield point = 38000…

Q: A 12 mm thick steel plate with five 25 mm hole is under a tension load as shown in Fig. 2. Assume…

Q: In tensile test the percentage of elongation was 29.8%. If the final length reached to 84.37mm, so…

Q: A cylindrical specimen of a brass alloy 13.6 mm in diameter has an ultimate tensile stress of 496…

Q: 13. An airplane’s landing gear must be capable of supporting ⅓ of its weight at 200000 kg. To induce…

A: Given Data The weigth of the aircraft is:W=200000 kg The yield strenght is:σyt=860 MPa The tensile…

Q: If the area under the stress and strain curve is less then it is concluded that the material has low…

A: The area under stress and strain curve represent the toughness of the specimen material.

Q: The yield strength of a high-strength steel is 1 GN/m2 and KIC is 100 MPa √m. The crack length that…

A: yield strength of a high-strength steel = 1 GN/m2 KIC = 100 MPa √m. The crack length that can cause…

Q: Determine the indentation diameter and the surface area of indentation of a copper material…

A: (i) Write a value of the Brinell Hardness Number (BHN). BHN=902 Write a diameter of the…

Q: 7. In the Brinell hardness test, if the load used 1200 kg, and the ball diameter 6 mm, write down…

Q: 1. A 10-mm-diameter Brinell hardness a steel alloy when a load of 500 kg was used. Compute the…

Q: gure t shows a compound bar with three different diameters, d1-9mm, d2-22mm, and d3-14mm machined…

A: Given Data: The diameter of section 1 is, d1=9 mm. The diameter of section 2 is, d2=22 mm. The…

Q: 2. A steel bar, whose cross section is 0.60 inch by 4.10 inches, was tested in ension. An axial load…

Q: What will be the length of given mild steel rod after applying 100 kips force/load ?. If the…

A: Given, Force applied = P = 100 kips = 100 x 103 lb Diameter of rod = d = 0.5 in Length of rod = L =…

Q: Necking in cast iron is seen when it is subjected to a tensile test. Select one: O True O False

Q: (i) Determine the Force applied on an aluminum specimen subjected to Brinell hardness test. If the…

A: Given data:- Surface area = 34 mm2 Brinell hardness number = 1234 Find :- Force applied = ?

Q: A typical value for the yield stress of mild steel would be? Select one: O a. 200 GPa O b. 100 MPa O…

A: Option c is correct.

Q: When a force is applied to a piece of material In such a manner as to twist it, the material is said…

A: A shaft is rigidly clamped at one end and twisted by a force at the other end then the shaft is in…

Q: At the proportional limit, a 18 mm thick 84 mm wide bar elongates 6.9 mm under an axial load of 495…

A: The change in width of the bar is -0.1242 mm.

Q: The true stress (in MPa) versus true strain relationship for a metal is given by O = 1020 e0.4 The…

A: As per question given data σ=1020∈0.4∈=0.4initial area A =100mm^2 we have to determine the cross…

Q: Determine the following i) Diameter of the specimen, i) Final length of the specimen, iii) Stress…

Q: A round brass rod 30 mm in diameter and 200 mm long is subjected to a compressive force of 100 kN.…

Q: Grade 1020 steel has a yield strength of 42 ksi and an elastic modulus of 30 Mpsi. Another grade of…

Q: If the Vicker’s hardness number (HVN) is 350 N/mm2, how much load was applied on the test specimen…

Q: In a tensile test is the maximum stress that developed in a material. Select one:

A: In a tensile test ________ is the maximum stress that developed in a material. Answer: d) Ultimate…

Q: B- Hardness test Brinell type was applied to copper alloy sample, 1 cm diameter steel ball was used…

Q: calculate hardness (Brilnell Hardness, HB): Ø Tested material – bronze Ø Force loading the…

Q: In a micro-Vickers hardness test, the diagonals of the indentation are 54 and 55 um when a load of…

A: d1 = 54 μm d2= 55 μm To find : Micro - Vickers harness (HV)

Q: 7. In the Brinell hardness test, if the load used 1200 kg, and the ball diameter 6 mm, write down…

A: Given Load(P)=1200kg, Diameter of the ball (D)=6mm, BHN=586

Q: A machine member is subjected to fluctuating stress O =0, cos(8 t). The endurance limit of the…

A: GIVEN DATA - σ=σo cos(8πt) σe=350MPa FACTOR OF SAFETY N=3.5 WE HAVE TO FIND VALYE OF ALLOWABLE…

Q: The steel rod in Fig. is to be used to support an axial load of 18 kip. If Est = 29(103 ) ksi and…

A: Given data: The applied load, P = 18 kip. The modulus of elasticity, E = 29 × 103 ksi. The yield…

Q: A thin-walled cylindrical pressure vessel made from a grade of aluminium has an internal diameter d…

Q: A mild steel material is subjected to a Brinell hardness test with an applied force of 7830 N using…

Q: A 10-mm-diameter Brinell hardness indenter produced an indentation 1.55 mm in diameter in a steel…

Q: 1- The diminutions of the mild steel impact test sample as shown in fig below and the notched depth…

A: As per policy only one question are allowed to be answered. For the remaining question please…

Q: 5. A member which does not regain its original shape after removal of the load producing deformation…

A: Let us first understand the meaning of each option. If the body does not allow any deformation under…

Q: C 300 kN 330 kN 30 mm t15 mm 20 mm +80 kN 250 mm- E150 mm e–200 mm

A: Given, d1 = 15 mm d2 = 30 mm d3 = 20 mm

Q: For a specimen with reported Rockwell B hardness number of RHB=93.8, the approximate value of…

A: Rockwell B hardness number=93.8

Concept explainers

Thermal Properties of Materials

In mechanical engineering, the thermal property is represented as the physical quantity that is relevant to the application of heat. The thermal properties are evaluated by variations in any specific material due to low heat or high heat. The quantities that influence the thermal property of the materials are mass, density, temperature, and many others.

Question

A Brinell hardness measurement of 650 HBN, using a 10-mm-diameter indenter and a 2950 kg load on an
aluminum plate. Determine the indentation diameter.
O a. 2.683 mm
O b. 2.836 mm
O c. 2.368 mm
O d. 2.386 mm

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Types of Properties of Engineering Materials

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions

If the Vicker’s hardness number (HVN) is 385 N/mm2, how much load was applied on the test specimen to make an indentation of 3.2 mm?
Which steel presents the maximum modulus of toughness UT? UT = ( (Sy − Sut) /2 ) ε f AISI 4142 and AISI 1020 AISI 1020 AISI 1095 and AISI 1020 AISI 4142 and AISI 1095
Determine the indentation diameter and the surface area of indentation of a copper material subjected to a Brinell hardness test with a test force of 7.3 kN using a hardened steel ball indentor of 11 mm. Take the Brinell Hardness Number as 948. Solution: i) Indentation Diameter (in mm) = ii) Surface Area of Indentation (in mm2) =
A test rod of rust-resistant steel, with a diam. of 12.8 mm and a measuring length of 50.8 mm is subjected to a tensile test. The data from the test is shown in the table below.
a tensile test is conducted for a metal wire which has a diameter of 4.7 the maximum recorded force was 3500N. Thus UTS point is :-??
The steel rod in Fig. is to be used to support an axial load of 18 kip. If Est = 29(103 ) ksi and sY = 50 ksi, determine the smallest diameter of the rod as allowed by the AISC specifications. The rod is fixed at both ends.
A 1∕2-in.-diameter round steel rod 40 ft long supports a loadof 4 kips. How much will it elongate? e= ΔL /L f = P/A E = (P∕A)/ (ΔL∕L) = (PL) / (A(ΔL))
A tensile force of 100 kN is applied on a 0.02-m diameter and 2-m long rod. After applying the load, the diameter of the rod decreases to 0.01998 m and the length increases to2.01 m. The true axialstrain is?
The key below is used to unscrew square head bolts. Determine the torsional stress of this tool. The cylinder is full. Answers: A) 1193 MPa B) 149 207 759 N/mm2 C) 149 Pa D) 2387 MPa
During the test of hardness due to Brinell, the diameter of the testing sphere was0.01m, the exerted load was 3.0 tons and the diameter of the indented area wasapproximately 0.003 m. Find the value of the hardness for this material. Also find theTensile strength if the proportionality constant was approximately 3.45.
For the steel bar shown in the fig. determine a) the total elongation of the bar b) the length of themiddle segment to have zero elongation of the bar c) the diameter of the last segment to have zeroelongation of the bar.
During a test, a copper specimen alloy having a diameter of 10.2 mm is applied with a tensile load of 8900 N. Given a maximum allowable elongation of 0.25 mm, determine the maximum length (mm) of the specimen before deformation.