A buffered solution of 0.0570 M Sbo* and 0.0200 M Cd²+ was prepared with a pH of 2.70 at 25 °C. Sbot + 2 H* + 3e¯= Sb(s) + H,0 Cd2+ + 2 e= Cd(s) Sbo+ = 0.208 V = -0.402 V E: Which ion is more easily reduced? Cd²+ O Sbot What is the concentration of SbOt at the potential when Cd²+ will begin to be deposited? [SbO*] = M Determine the potential at the cathode when the SbOt concentration is 0.0019 M? Ecathode V

A buffered solution of 0.0570 M Sbo* and 0.0200 M Cd²+ was prepared with a pH of 2.70 at 25 °C. Sbot + 2 H* + 3e¯= Sb(s) + H,0 Cd2+ + 2 e= Cd(s) Sbo+ = 0.208 V = -0.402 V E: Which ion is more easily reduced? Cd²+ O Sbot What is the concentration of SbOt at the potential when Cd²+ will begin to be deposited? [SbO*] = M Determine the potential at the cathode when the SbOt concentration is 0.0019 M? Ecathode V

Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Chapter24: Coulometry

Section: Chapter Questions

Problem 24.5QAP: What cathode potential (versus SCE) would be required to lower the total Hg(II) concentration of the...

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