A built-up section was made using PL414x12mm thk plates as shown in the figure below. It is pinned at both ends with additional support against weak axis at middle point. Assume A50 steel. PL414x12 08 Section W16x67 L x-axis Elevation www ANANAN y-axis
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- Compute the nominal shear strength of an M107.5 of A572 Grad 65 steel.Compute the nominal shear strength of an M1211.8 of A572 Grade 65 steel.A 15" x 3/8" bar of A572 Gr. 50 steel is used as a tension member. It is connected to a gusset plate with 7/8-in diameter bolts as shown in the figure. Use s = 2.0 and g = 3.0. Determine the allowable tensile strength of the section based on tensile rupture of the net area.
- Steel design. The lap joint shown consist of bolts 22mm in diameter in 25mm diameter holes, The plates are A36 steel with Fy=250MPa, and Fu=400MPa. Use x1=50 mm ,x2= 160mm ,x3=60mm and plate thickness t=12mm for this problem. The allowable stress are: Bearing stress on project are,Fc=1.5Fu Tension on the net area of plates,Ft=0.5Fu Shear on the plates, Fv=0.3Fu Shear strength of bolt,Fv=210MPa Det. the value of Load P based on bolt shear Det. the value of Load P base on bearing on projected area on plate. Det. the value of load P based on block shearpls help! Write the complete solutions and legibly. Answer in 2 decimal places. UPVOTE WILL BE GIVEN! MECHANICS OF DEFORMABLE BODIES Let Q = 0 and T = 8 (Example: 12Q°C = 120°C). Just substitute the number in letter. Thank you! For the frame shown, a 4QQT-N load is acting on member ABD at D. If the allowable material shear stress for is 4Q MPa, determine the required diameter (rounded off to the nearest 2.5 mm) of the pins at C and D. Pin C and pin D are subjected to double shear and single shear, respectively. If the thickness of member BC is 12 mm and that of member DE is 16 mm, determine the maximum bearing stress at C.A 15" x 3/8" bar of A572 Gr. 50 steel is used as a tension member. It is connected to a gusset plate with 7/8-in diameter bolts as shown in the figure. Use s = 2.0 and g = 3.0. Determine the design tensile strength of the section based on tensile rupture of the net area. Determine the allowable tensile strength of the section based on yielding of the gross area.
- Prob 01: An 18” depth beam is bolted to a 24” depth girder is connected similar to that in figure shown below. Thediameter of the rivet is 20mm and the angles are each 100mm x 100mm x 12mm thick. For each bolt, assume thatthe allowable bearing stress is 220 MPa. Determine the allowable load P in KN on the connection. *show all theload P in kN for bearing stressBeam web thickness = 5mmGirder web thickness =A W16x45 (A992 steel) (see below) is used in tension and connected to a plate on each flange. Determine the nominal strength based on the effective area (Ae) two ways: First, use the usual shear lag factor equation U = 1 –(?̅/L). Next use the alternative ‘U’ value from AISC Table D3.1.A 15" x 3/8" bar of A572 Gr. 50 steel is used as a tension member. It is connected to a gusset plate with 7/8-in diameter bolts as shown in the figure. Use s = 2.0 and g = 3.0. a) Determine the allowable tensile strength of the section based on tensile rupture of the net area.b) Determine the allowable tensile strength of the section based on yielding of the gross area.
- A double channel shape is used as a tension member. The channels are bolted to a gusset plate with 22mm diameter bolts. Fy-channel = 345 MPa, Fu-channel = 450 MPa Fy-plate = 248 MPa, Fu-plate = 400 MPa Achannel = 3555 mm^2, tw = 12.18 mm, Shear lag factor = 0.90 A. Determine the ultimate tensile strength of the tension member based on its gross area.The angle bracket shown, 75 mm x 75 mm x 15 mm thick, is 200 mm long. It is connected to the 16 mm thick flange of the column support with 2 of 16 mm diameter bolts. The bracket is subjected to a load of 42 kN from beam A. Assume that the load is applied concentrically at the connection. 1. Determine the resulting bolt shear stress in MPa 2. Determine the resulting bolt shear stress in MPa 3. Determine the critical bolt shearing stress in MPaA W14X120 is used as a tension member in atruss. The flanges of the member are connected to a gusset plate by ¾ inch boltas shown below. Use A36 steel with Fy=36 ksi and Fu=58 ksi A. Determine the Yielding Capacity of the section based on LRFD (kips) Round your answer to 2 decimal places. c. Determine the Tensile Rupture capacity of the section based on LRFD need answer please