A carbonate mixture was titrated with 0.1100 M HCI. The sample weighing 850.0 mg took 21.00 mL to reach the phenolphthalein end point and an additional 14.00 mL to reach the methyl red end point. Calculate the weight percentage of the component/s.
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- An experiment to observe the effect of ionic strength on the solubility of Ca(OH)2 was conducted. Ca(OH)2 was added to 250 mL 0.01 M KCl, stirred until equilibrium. This was then filtered, and 50 mL of the filtrate was measured out. The 50 mL filtrate was then titrated with standardized 0.13 M HCl solution until phenolphtalein endpoint (11 mL). How do I solve for the solubility s of Ca(OH)2? Please provide an explanation of the process (do I multiply ionic strength μ to the solubility [where s = [Ca(OH)2) = [Ca2+] = 1/2[OH-]?)An experiment to observe the effect of ionic strength on the solubility of Ca(OH)2 was conducted. Ca(OH)2 was added to 250 mL 0.01 M KCl, stirred until equilibrium. This was then filtered, and 50 mL of the filtrate was measured out. The 50 mL filtrate was then titrated with standardized 0.13 M HCl solution until phenolphtalein endpoint (11 mL). How do I solve for the solubility s of Ca(OH)2? Please provide an explanation of the process (do I multiply ionic strength μ to the solubility [where s = [Ca(OH)2) = [Ca2+] = 1/2[OH-]?) I would like to know how the diverse ion effect would affect the solubility of Ca(OH)2. How does the ionic strength μ of KCl affect this?Mr. Clean recently bought a laboratory-grade sodium carbonate from a chemical company known as Brand X. He was supposed to use it in the production of detergents. Unfortunately, he was scammed by the company. He suspected that he purchased a crude sodium carbonate so he tasked the Quality Assurance Department to determine the components of the purchased chemical. The chemist assigned to analyze the sample used double indicator method. For the standardization of HCl titrant, 0.1025 g Na2CO3 of 99.5% purity (FW: 106.00) required 8.20 mL of the titrant to reach the phenolphthalein endpoint. FW: NaOH (40.00), NaHCO3 (84.01), Na2CO3 (106.00) a. What is the molarity of the titrant? The chemist obtained a 3.150 g sample and dissolved it in distilled water to produce a 50.0 mL solution. An aliquot of 10.00 mL was obtained and diluted in a 100.0 mL volumetric flask. A 50.00-mL aliquot of the diluted sample was taken and it required 25.70 mL of titrant for the methyl orange endpoint, while…
- A double indicator analysis of a soda ash sample was performed. The student weighed 0.4375 g of the soda ash sample and dissolved it to make 100.0 mL solution. The students then took a 25 mL aliquot of the sample solution, then added 25 mL H2O and performed double indicator titration. The phenolphthalein endpoint required 10.27 mL 0.04027 M HCl titrant. The sample was further titrated using Methyl Orange and took a total of 15.97 mL of the titrant to reach the endpoint. Given that the molar weight of Na2CO3 - 105.99 g/mol, NaHCO3 = 84.007 g/mol, and NaOH - 39.997 g/mol answer the following: a. What are the components of the soda ash sample? (The constituents of the sample came from Na2CO3, NaHCO3, and NaOH). b. What are the moles of each component in the titrated 25 mL aliquot? c. What is the percent composition in (% w/w) of each component in the soda ash sample?A 0.1214-g sample of impure Na2CO3 was analyzed by the Volhard method. After adding 50.00 mL of 0.07011 M AgNO3, the sample was back titrated with 0.06021 M KSCN, requiring 27.15 mL to reach the end point. State the net ionic equation.A sample is analyzed for chloride by the Volhard method. From the following data, calculate the percentage of chloride present:Weight of sample = 6.0000 g dissolved and diluted to 200 mLAliquot used = 25.00 mL AgNO3 added = 40.00ml of 0.1234MKSCN for back titration = 13.20ml of 0.0930M
- A 0.15mL of phenolphthalein indicator was dropped to 10.00mL of an unknown acid. Then, 52.00mL from the 100mL of 10M NaOH Solution was placed in a 50mL burette. A titration experiment was done using the 10.15mL unknown acid with phenolphthalein indicator as analyte and the 52mL of NaOH as titrant. The solution turned pink when the final volume of the analyte was 10.68mL and the final reading in the burette was 51.47mL. What is the concentration of the unknown acid?1ml of 1mg/ml of diluted aspirin powder solution is titrated by 0.005M NaOH. Before titration, 5 ml ethanol, 14 ml CO2 free water, and 4 drops bromothymol blue indicator is added into diluted aspirin powder solution. Mass of 0.005M NaOH used is obtained by weight titration = 1.1384g . [Molar mass of aspirin =180.15]; for solution, 1g=1mL at 25 degree Celcius. Calculate the purity of the powder.A commercial vinegar was analyzed by titration to determine the percent acetic acid. Briefly, 10.00 mL of vinegar sample was diluted to 100. mL solution in a volumetric flask. A 25.00 mL aliquot from the diluted vinegar required 25.55 mL of 0.1005 M sodium hydroxide to reach the phenolphthalein endpoint From this experiment which is the standard solution used in titration? CH3COOH NaOH NaCH3COO C20H14O4
- A titrant solution of KMnO was standardized with 0.2000 grams of Na2C2O4 and consumed 27.75 mL to reach end point. Calculate the standardized NORMAL concentration of the titrant.A mixture of 500.0 mg acid A and 250.0 mg acid B is titrated with 0.1150 N NaOH. The endpoint is overstepped on the addition of 45.30 mL of the base. The solution is backtitrated using 1.40 mL of 0.1234 N HCl solution. If the equivalent weight of A is thrice the equivalent mass of B, calculate the equivalent weights of A and B.A commercial lab received a batch of industrial wastewater samples for analysis. Johnplans to test water hardness of these unknown samples. Prior to complexometric titration,the titrant, EDTA solution needs to be standardized. A 50.00 mL of 5.67 x10-3 M Ca2+standard solution required average of 38.10 mL of unknown EDTA solution to reach itsend point. Based on titration information recorded, work out the correct molarity of EDTAsolution.