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A certain nonvolatile hydrocarbon that weighed 1.00 g was dissolved in 50.00 g of benzene. The resulting solution was boiled at 0.285 °C higher than the boiling point of pure benzene which boils at 80.1°C. Find the molar mass of the hydrocarbon. (Hint: See Table 1 for given constant.)

A certain nonvolatile hydrocarbon that weighed 1.00 g was dissolved in 50.00 g of benzene. The resulting solution was boiled at 0.285 °C higher than the boiling point of pure benzene which boils at 80.1°C. Find the molar mass of the hydrocarbon. (Hint: See Table 1 for given constant.)

Principles of Modern Chemistry
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter14: Chemical Equilibrium
Section: Chapter Questions
Problem 93AP
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Problem Solving: 1. A solution is made of 2.00 g of sucrose, C12H22011, in water, H20. The molar mass (MM) of sucrose is 342 g/mol. Calculate the (a) boiling point and (h) freezing point of the solution. (Hint: See Table 1 for given constants.) 2. A certain nonvolatile hydrocarbon that weighed 1.00 g was dissolved in 50.00 g of benzene. The resulting solution was boiled at 0.285 °C higher than the boiling point of pure benzene which boils at 80.1°C. Find the molar mass of the hydrocarbon. (Hint: See Table 1 for given constant.) 14
Transcribed Image Text:Problem Solving: 1. A solution is made of 2.00 g of sucrose, C12H22011, in water, H20. The molar mass (MM) of sucrose is 342 g/mol. Calculate the (a) boiling point and (h) freezing point of the solution. (Hint: See Table 1 for given constants.) 2. A certain nonvolatile hydrocarbon that weighed 1.00 g was dissolved in 50.00 g of benzene. The resulting solution was boiled at 0.285 °C higher than the boiling point of pure benzene which boils at 80.1°C. Find the molar mass of the hydrocarbon. (Hint: See Table 1 for given constant.) 14
Table 1. Molal Freezing Point and Boiling Point Constants Freezing Point (C) Solvent Formula Bolling Point (*C) (C/molal) (c/molal) Water H20 0.0 1.86 100.0 0.51 Acetic acid CH:COOH 17.0 3.90 118.1 3.07 Benzene 5.5 4.90 80.2. 2.53 Chloroform CHC3 -63.5 4.68 61.2 3.63 Ethanol C2H5OH 114.7 1.99 78. 78.4 1.22 7.40 181.0 3.56 Phenol CeHsOH 43.0
Transcribed Image Text:Table 1. Molal Freezing Point and Boiling Point Constants Freezing Point (C) Solvent Formula Bolling Point (*C) (C/molal) (c/molal) Water H20 0.0 1.86 100.0 0.51 Acetic acid CH:COOH 17.0 3.90 118.1 3.07 Benzene 5.5 4.90 80.2. 2.53 Chloroform CHC3 -63.5 4.68 61.2 3.63 Ethanol C2H5OH 114.7 1.99 78. 78.4 1.22 7.40 181.0 3.56 Phenol CeHsOH 43.0
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