Calculating the pH at equivalence of a titrationA chemist titrates 210.0 mL of a 0.2223M pyridine (C,H,N) solution with 0.3895M HNO, solution at 25 °C. Calculate the pH at equivalence. The p K, ofpyridine is 8.77.Round your answer to 2 decimal places.Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HNO, solution added.pH =II

Given: Volume of C5H5N = 0.2223 M Volume of C5H5N solution = 210.0 mL = 0.210 L…

A chemist titrates 210.0 mL of a 0.2223M pyridine (C,H,N) solution with 0.3895M HNO, solution at 25 °C. Calculate the pH at equivalence. The p K, pyridine is 8.77. Round your answer to 2 decimal places.

A chemist titrates 210.0 mL of a 0.2223M pyridine (C,H,N) solution with 0.3895M HNO, solution at 25 °C. Calculate the pH at equivalence. The p K, pyridine is 8.77. Round your answer to 2 decimal places.

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter16: Reactions Between Acids And Bases

Section: Chapter Questions

Problem 16.54QE

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Concept explainers

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

Question

Calculating the pH at equivalence of a titration
A chemist titrates 210.0 mL of a 0.2223M pyridine (C,H,N) solution with 0.3895M HNO, solution at 25 °C. Calculate the pH at equivalence. The p K, of
pyridine is 8.77.
Round your answer to 2 decimal places.
Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HNO, solution added.
pH =
II

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