A chi-square test of independence value of =27.05 is calculated from data in a 4 × 5 contingency table. Assuming a .05 level of significance,What is the degree of freedom?Identify the critical value.Do you reject, or fail to reject, the null hypothesis?

Answered: A chi-square test of independence value…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A chi-square test of independence value of =27.05 is calculated from data in a 4 × 5 contingency table. Assuming a .05 level of significance,
1. What is the degree of freedom?
2. Identify the critical value.
3. Do you reject, or fail to reject, the null hypothesis?

Expert Solution

Step 1

(1)

Determine the degrees of freedom.

The degrees of freedom is obtained below as follows:

From the information, given that there is 4 × 5 contingency table.

The required degrees of freedom is,

The degrees of freedom is 12.

Step 2

(2)

Obtain the critical value.

The critical value is obtained below as follows:

Follow the instruction to obtain the chi square critical value:

Open EXCEL
Go to Formula bar.
In formula bar enter the function as“=CHIINV”
Enter the probability as 0.05
Enter the degrees of freedom as 12
Click enter

EXCEL output:

The critical value of Chi square at the 0.05 level of significance with the 12 degrees of freedom is 21.0261.

Thus, the critical value is 21.0261.

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