(a) Clearly state the test hypotheses (b) Use an appropriate formula to calculate the expected counts. (c)Use an appropriate formula to calculate the degree of freedom. Do not do the rest
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Ninety-five r/s blue-collar workers and 50 r/s white-collar workers from a company are
asked about their views on a certain company issue, and their responses are classified by
the following two-way table. We wish to determine whether these results provide
significant evidence that the opinion of a worker depends on the job type.
blue-collar workers | white-collar workers | |||
In favor | 44 | 21 | ||
Oppose | 39 | 26 | ||
No opinion | 12 | 3 | ||
(a) Clearly state the test hypotheses
(b) Use an appropriate formula to calculate the expected counts.
(c)Use an appropriate formula to calculate the degree of freedom. Do not do the rest
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- An agency reports that 11.5% of workers in a particular country belonged to unions. Suppose a sample of 300 workers is collected to determine whether union efforts to organize have increased union membership. (a) Formulate the hypotheses that can be used to determine whether union membership has increased. H0: p ≥ 0.115 Ha: p < 0.115 H0: p = 0.115 Ha: p ≠ 0.115 H0: p ≤ 0.115 Ha: p > 0.115 H0: p < 0.115 Ha: p ≥ 0.115 H0: p > 0.115 Ha: p ≤ 0.115 (b) If the sample results show that 42 of the workers belonged to unions, what is the p-value for your hypothesis test? Find the value of the test statistic. (Round your answer to two decimal places.) ( ) Find the p-value. (Round your answer to four decimal places.) p-value = ( ) (c) At ? = 0.05, what is your conclusion? Do not reject H0. There is insufficient evidence to conclude that there has been an increase in union membership. Reject H0. There is sufficient evidence to conclude that…An organization published an article stating that in any one-year period, approximately 7.5 percent of adults in a country suffer from depression or a depressive illness. Suppose that in a survey of 100 people in a certain town, six of them suffered from depression or a depressive illness. Conduct a hypothesis test to determine if the true proportion of people in that town suffering from depression or a depressive illness is lower than the percent in the general adult population in the country.In an experiment with the effect of different feeding on sheep fertility, two feed categories were examined, A and B. 192 rivers were given feed category A and 190 were given feed category B. The following number of monocotyledonous and dicotyledonous sheep were obtained in each category: Feed category A Feed category B Monocotyledonous 60 82 Dicotyledonous 132 108 Examine with an appropriate hypothesis test whether there is a difference in fertility by feed category.
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- A random sample of n1 = 10 regions in New England gave the following violent crime rates (per million population). x1: New England Crime Rate 3.3 3.7 4.0 3.9 3.3 4.1 1.8 4.8 2.9 3.1 Another random sample of n2 = 12 regions in the Rocky Mountain states gave the following violent crime rates (per million population). x2: Rocky Mountain Crime Rate 3.5 4.3 4.5 5.1 3.3 4.8 3.5 2.4 3.1 3.5 5.2 2.8 Assume that the crime rate distribution is approximately normal in both regions. (i) Use a calculator to calculate x1, s1, x2, and s2. (Round your answers to three decimal places.) x1 = s1 = x2 = s2 = (ii) Do the data indicate that the violent crime rate in the Rocky Mountain region is higher than in New England? Use α = 0.01.(a) What is the level of significance? What is the value of the sample test statistic? (Test the difference μ1 − μ2. Round your answer to three decimal places.)A major oil company has developed a new gasoline additive that is supposed to increase mileage. To test this hypothesis, ten cars are randomly selected. The cars are driven both with and without the additive. The results are displayed in the following table. Can it be concluded, from the data, that the gasoline additive does significantly increase mileage? Car Without additive 25.5 27.7 19.5 22.4 9.9 21.1 13.1 26.7 20.6 24.9 With additive 25.7 28.6 21.4 25.7 13.4 21.7 14.6 30 23 26.5A random sample of n1 = 10 regions in New England gave the following violent crime rates (per million population). x1: New England Crime Rate 3.6 3.9 4.8 3.2 3.3 4.1 1.8 4.8 2.9 3.1 Another random sample of n2 = 12 regions in the Rocky Mountain states gave the following violent crime rates (per million population). x2: Rocky Mountain Crime Rate 3.7 4.0 4.5 5.2 3.3 4.8 3.5 2.4 3.1 3.5 5.2 2.8 Assume that the crime rate distribution is approximately normal in both regions. Note: If a two-sample t-test is appropriate, for degrees of freedom d.f. not in the Student's t table, use the closest d.f. that is smaller. In some situations, this choice of d.f. may increase the P-value by a small amount and therefore produce a slightly more "conservative" answer.Use a calculator to calculate x1, s1, x2, and s2. (Round your answers to two decimal places.) x1 = s1 = x2 = s2 = (a) Do the data indicate that the violent crime rate in the Rocky Mountain…
- A random sample of n1 = 10 regions in New England gave the following violent crime rates (per million population). x1: New England Crime Rate 3.3 3.7 4.0 4.1 3.3 4.1 1.8 4.8 2.9 3.1 Another random sample of n2 = 12 regions in the Rocky Mountain states gave the following violent crime rates (per million population). x2: Rocky Mountain Crime Rate 3.5 4.3 4.5 5.3 3.3 4.8 3.5 2.4 3.1 3.5 5.2 2.8 Assume that the crime rate distribution is approximately normal in both regions. Do the data indicate that the violent crime rate in the Rocky Mountain region is higher than in New England? Use α = 0.01. Solve the problem using both the traditional method and the P-value method. (Test the difference μ1 − μ2. Round the test statistic and critical value to three decimal places.) test statistic critical value REM (rapid eye movement) sleep is sleep during which most dreams occur. Each night a person has both REM and non-REM sleep. However, it is thought that…A random sample of n1 = 10 regions in New England gave the following violent crime rates (per million population). x1: New England Crime Rate 3.3 3.7 4.2 3.9 3.3 4.1 1.8 4.8 2.9 3.1 Another random sample of n2 = 12 regions in the Rocky Mountain states gave the following violent crime rates (per million population). x2: Rocky Mountain Crime Rate 3.5 4.1 4.7 5.5 3.3 4.8 3.5 2.4 3.1 3.5 5.2 2.8 Assume that the crime rate distribution is approximately normal in both regions. Do the data indicate that the violent crime rate in the Rocky Mountain region is higher than in New England? Use ? = 0.01. Solve the problem using both the traditional method and the P-value method. (Test the difference ?1 − ?2. Round the test statistic and critical value to three decimal places.) test statistic critical value Find (or estimate) the P-value. A. P-value > 0.250 B. 0.125 < P-value < 0.250 C. 0.050 < P-value < 0.125 D. 0.025 < P-value <…A random sample of n1 = 10 regions in New England gave the following violent crime rates (per million population). x1: New England Crime Rate 3.5 3.9 4.0 4.1 3.3 4.1 1.8 4.8 2.9 3.1 Another random sample of n2 = 12 regions in the Rocky Mountain states gave the following violent crime rates (per million population). x2: Rocky Mountain Crime Rate 3.7 4.1 4.7 5.1 3.3 4.8 3.5 2.4 3.1 3.5 5.2 2.8 (a) Assume that the crime rate distribution is approximately normal in both regions. Use a calculator to calculate x1, s1, x2, and s2. (Round your answers to two decimal places.) x1 = s1 = x2 = s2 = (b) What is the value of the sample test statistic? Compute the corresponding z or t value as appropriate. (Test the difference μ1 − μ2. Do not use rounded values. Round your answer to three decimal places.) (c) Find a 98% confidence interval for μ1 − μ2. (Round your answers to two decimal places.) lower limit upper limit