A company manufactures printers and fax machines at plants located in Atlanta, Dallas, and Seattle. To measure how much employees at these plants know about quality management, arandom sample of 6 employees was selected from each plant and the employees selected were given a quality awareness examination. The examination scores for these 18 employees are shownin the following table. The sample means, sample variances, and sample standard deviations for each group are also provided. Managers want to use these data to test the hypothesis that themean examination score is the same for all three plants.Plant 2 Plant 3Plant 1AtlantaDallasSeattle847059757464817361757369716876948661Samplemean807465Sample68.839.641.2varianceSamplestandard 8.296.296.42deviationSet up the ANOVA table for these data. (Round your values for MSE and F to two decimal places, and your p-value to four decimal places.)SourceSumDegreesMeanFp-valueof Squares of FreedomSquareof VariationTreatmentsErrorTotalTest for any significant difference in the mean examination score for the three plants. Use α = 0.05.State the null and alternative hypotheses.OH₁₂H₁₂ = H₂ = H₂H: Not all the population means are equal.ⒸH₁ H₂ H₂ H3OH,: Not all the population means are equal.H₂H₂ = H₂ = 13OH₁₂¹ H₂ = H₂ = H₂OH: At least two of the population means are equal.H₂: At least two of the population means are different.Find the value of the test statistic. (Round your answer to two decimal places.)Find the p-value. (Round your answer to four decimal places.)p-value =State your conclusion.O Do not reject H. There is sufficient evidence to conclude that the means for the three plants are not equal.O Do not reject H. There is not sufficient evidence to conclude that the means for the three plants are not equal.O Reject H. There is not sufficient evidence to conclude that the means for the three plants are not equal.O Reject H. There is sufficient evidence to conclude that the means for the three plants are not equal.

Question

Accepted Answer

Solution:
Given information:
k= 3 groups or treatments 
Each group has 6 observation
n= 18 total…