A compound, C₂H, CIO, has an IR spectrum showing a peak at 1810 cm1. Its ¹H NMR spectrum has peaks at delta 1.0 (3 H. triplet), 1.7 (2 H, multiplet), and 2.8 (2 H, triplet). Draw its structure in the window below. • You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. • Do not include lone pairs in your answer. They will not be considered in the grading. 1985 0 ▾ Ⓒ • Sn [F ChemDoodleⓇ 25

A compound, C₂H, CIO, has an IR spectrum showing a peak at 1810 cm1. Its ¹H NMR spectrum has peaks at delta 1.0 (3 H. triplet), 1.7 (2 H, multiplet), and 2.8 (2 H, triplet). Draw its structure in the window below. • You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. • Do not include lone pairs in your answer. They will not be considered in the grading. 1985 0 ▾ Ⓒ • Sn [F ChemDoodleⓇ 25

Organic Chemistry

9th Edition

ISBN:9781305080485

Author:John E. McMurry

Publisher:John E. McMurry

Chapter12: Structure Determination: Mass Spectrometry And Infrared Spectroscopy

Section12.SE: Something Extra

Problem 16AP: Camphor, a saturated monoketone from the Asian camphor tree, is used among other things as a moth...

See similar textbooks

Similar questions

I have the following data from an NMR scan. Five peaks; a doublet at about 0.8ppm (6H) a small single septet at about 1.5 ppm (1H), a triplet at 1.6 ppm (2H(, a singlet at about 2.1 ppm (3H), a triplet at about 4.4 ppm (2H). The molecular formula is C7H14O2. I calculated a degree of unsaturation of 1. I have tentatively identified the compound as methyl-4-methylbutanoate. I would appreciate any comments you care to make. Thank you.
HURRY ASAP I WILL RATE NO NEED FOR EXPLANATION WHICH OPTIN Which one of the following statements about compounds given below is true? Compound 1 Compound 2 CH3CH2SH CH3CH2OH Hydrogen bond strength of compound 1 is less than compound 2 Compound 2 is more easily oxidized than compound 1 Boiling point of compound 1 is more than compound 2 Acid strength of compound 1 is less than compound 2 Compound 1 is more polar than compound 2
Draw the structure of the one tertiary (3°) amine with molecular formula C5H13N that does not contain a 3-carbon chain. You do not have to consider stereochemistry. You do not have to explicitly draw H atoms
An IR spectra show C—H peaks in the functional group region at values 2990 and 2890 cm^-1, but does not show any C—H peaks above 3000 cm^-1. What can be concluded about this compound? This compound only contains H’s bonded to sp3 carbons. This compound only contains H’s bonded to sp2 carbons. This compound only contains H’s bonded to sp carbons. This compound only contains H’s bonded to sp and sp2 carbons.
Compound A has the formula C5H10O that is produced by oxidation of a conpound that has the formula C5H12O. Compound A has an IT spectrum the has an absorbance at 1700 cm^-1 and no broad absorbance from 2500-3500 cm^-1. The 1H and 13C spectrums of Compound A both have 4 peaks. What is tbe structure of Compound A? Thank you for the help!
Compounds B and C are isomers with molecular formula C5H9BrO2. The 1H NMR spectrum of compounds B and C are shown below. The IR spectrum corresponding to compound B showed strong absorption bands at 1739, 1225, and 1158 cm-1, while the spectrum corresponding to compound C have strong bands at 1735, 1237, and 1182 cm-1. 1.Based on the information provided, determine the structure of compounds B and C. 2.Assign all peaks in 1H NMR spectrum of compounds B and C.
Compound A has molecular formula C7H7X. Its 1H-NMR spectrum shows a singlet at 2.25 ppm and two doublets, one at 7.28 ppm and one at 7.39 ppm. The singlet has an integral of three and the doublets each have an integral of two. The mass spectrum of A shows a peak at m/z = 126 and another peak at m/z = 128; the relative height of the two peaks is 3:1 respectively. - Identify what atom X is, explaining your reasoning - Identify Compound A, explaining your reasoning
ANSWER ALL QUESTIONS 1. write out all the isomers of the compound with molecular formula C4H10O. 2. select the normal/primary isomer and treat it with conc.H2SO4 and heat to produce A. Identify the type of reaction 3. Treatment of A with HCl/H2O gives B and with cold KMnO4/ OH- gives C . Give the name and structures of A, B and C 4. Treatment of A with Hot KMnO4/OH- gives D followed by acidification of the mixture to give E. What is D and E ?
An unknown compound has a molecular formula of C3H6O2. Its IR spectrum shows a very strong and broad band at 2980 and a strong sharp peak at 1716 cm-1. It exhibits the following signals in its 1H NMR spectrum (ppm): 1.21 (triplet, 3H), 2.48 (quartet, 2H), 11.7 (singlet, 1H); and the following signals in its 13C NMR spectrum (ppm): 8.9, 27.6, 181.5. Draw the structure of the unknown compound.
Three isomeric compounds, A, B, and C, all have molecular formula C8H11N. The 1H NMR and IR spectral data of A, B, and C are given below. What are their structures?
15. Compound C has a molecular weight of 94.54 and the 1H-NMR spectrum shows four signals - a triplet at 3.81 ppm, a triplet at 3.63 ppm, a singlet at 2.19 ppm, and a triplet of triplets at 2.02 ppm. The mass, IR, and 13C-NMR spectra of compound C are shown below, they are also downloadable for closer inspection by clicking the link under the spectral data. Identify C and explain your reasoning. refer to picture
Compound B of molecular formula C9H19N shows a noteworthy infrared absorption at 3300 cm-1. Its 1H-NMR spectrum shows three singlets – δ 1.0 (6H), 1.1 (12H), 1.4 (1H) ppm. Its 13C-NMR spectrum has four signals – δ 25, 28, 41, 64 ppm. Suggest a structure for this compound.