E = h vE = hc / wavelenegthwavelength = c / vc = 3.00 x 108 m /sh = 6.626 x 10-34 J. s1 nm = 1 x 10-9 mAvogadro's number: 6.022 x 1023total electron groupgroup geometrynumber of surrounded atoms number of lone pair of electronsmolecular shape 2linear 20linear 3trigonal planar 3 20 1trigonal planar bent or angular 4 tetrahedral 4 3 2 0 1 2 tetrahedral trigonal pyramidal bent or angular A compound contains 77.73% Fe and 22.27% O by mass. Calculate the empirical formula.Fe = 55.85 g/ mole and O = 16.00 g/moeGroup of answer choicesA.) FeOB.) Fe2O3C.) FeO2D.) Fe3O4

given :- % by mass of Fe = 77.73% % by mass of O = 22.27% MW of Fe = 55.85 g/mol MW of O = 16.00…

Answered: A compound contains 77.73% Fe and…

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter6: Quantum Mechanics And Molecular Structure

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E = h v

E = hc / wavelenegth

wavelength = c / v

c = 3.00 x 10⁸ m /s

h = 6.626 x 10^-34 J. s

1 nm = 1 x 10^-9 m

Avogadro's number: 6.022 x 10²³

total electron group	group geometry	number of surrounded atoms	number of lone pair of electrons	molecular shape
2	linear	2	0	linear
3	trigonal planar	3 2	0 1	trigonal planar bent or angular
4	tetrahedral	4 3 2	0 1 2	tetrahedral trigonal pyramidal bent or angular

A compound contains 77.73% Fe and 22.27% O by mass. Calculate the empirical formula.

Fe = 55.85 g/ mole and O = 16.00 g/moe

Group of answer choices

A.) FeO

B.) Fe2O3

C.) FeO2

D.) Fe3O4

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