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Asked Dec 3, 2019
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A concentration cell is set up using two zinc wires and two solution, one containing 0.400 M ZnCl2 solution and the other containing 1.60 M Zn(NO3)2 solution. Compute the potential of this cell.

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Step 1

Half-cell reactions ar...

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[At anode] Zn(s) →Zn² (aq)+ 2e¯ [At cathode] Zn 2* (aq) + 2e - →Zn(s)

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