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A digital watch battery draws 0.35 milliamperes of current, which is provided by a mercury battery whose net reaction is:HgO(s) + Zn(s) → ZnO(s) + Hg(l)If a partially used battery contains 1.90 g of each of these four substances, for how many hours will the watch continue to run?

Question

A digital watch battery draws 0.35 milliamperes of current, which is provided by a mercury battery whose net reaction is:

HgO(s) + Zn(s) → ZnO(s) + Hg(l)

If a partially used battery contains 1.90 g of each of these four substances, for how many hours will the watch continue to run?

check_circleAnswer
Step 1

The approach to this problem is to find the limiting reagent and then calculating the charge.

Step 2

First step is to give the half reactions.  This can be given as,

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Step 3

An ampere is a unit of charge per time (Coulomb per second).  There are 2 electrons that pass into conduction.  During this react...

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