a dilution is needed to prepare a standard of 10 mg Zn/L from 0.5g Zn/L. To carry out the dilution we have the following available bulb pipettes: 1ml,2ml,5ml,10ml,20ml and 25 ml and the following volumetric flask: 50ml,100ml, 250ml,500ml. which bulb pipette and which corresponding volumetric flask you would choose to carry out the dilution?
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- A sample containing chlorophenol, C6H4ClOH, was analysed by gravimetric analysis. A 0.783-g of this sample goes through a chemical process allowing the chlorine in the chlorophenol to precipitate as silver chloride, weighing 0.271 g. Calculate the % (wt/wt) of the chlorophenol in the sample, assuming that chlorophenol is the only source of chlorine in the sample. Provide your answer to two decimal places and without units. Avoid using scientific notation.Consider the titration illustrated in Figure 8.] Anhydrous sodium carbonate (Na₂CO₃) is a primary standard. When 0.364 grams of the substance is placed in a conical flask, then 20.00 cm³ of sulphuric acid (H₂SO₄) solution is required to reach the end point of the titration. What is the concentration in mol·dm⁻³ of the sulphuric acid solution? [Give the answer to 3 decimal places. Do not type in the unit. Use a decimal point.] *A pipet is used to transfer 3.00 mL of a 2.00 M stock solution in flask “S” to a 25.00-mL volumetric flask “A,” which is then diluted with DI H2O to the calibration mark. The solution is thoroughly mixed. Next, 3.00 mL of the solution in volumetric flask “A” is transferred by pipet to a 50.00-mL volumetric flask “B” and then diluted with DI H2O to the calibration mark. Calculate the molarity of the solution in volumetric flask “B.”
- A K2SO4 solution is prepared by weighing out a certain amount of the pure solid reagent,dissolving it to 500.0 mL in a volumetric flask. An aliquot was taken from this solution.of 25.00 ml and diluted to 500.0 ml. An aliquot of 5.00 was taken from this new solution anddiluted to 50.00 ml. A chemical analysis of this new solution showed a 0.100%(w/v)in K+. Calculate the weight of the pure solid K2SO4 used for the preparation of the original solution.and its concentration in each volumetric flask. The answer is 2.23x10^2gA pipet is used to transfer 5.00 mL of a 1.25 M stock solution in flask “S” to a 25.00-mL volumetric flask “B,” which is then diluted with DI H2O to the calibration mark. The solution is thoroughly mixed. Next, 3.00 mL of the solution in volumetric flask “A” is transferred by pipet to a 50.00-mL volumetric flask “B” and then diluted with DI H2O to the calibration mark. Calculate the molarity of the solution in volumetric flask “B.”6. A stock solution containing 25% w/v of chlorhexidine is used to prepare an antiseptic such that when the antiseptic is diluted 1 in 25, a 1 in 500 wash solution is obtained which is ready for use by the patient. What volume (ml) of the stock solution is required to prepare 5 litres of the antiseptic to fulfil a bulk manufacturing order?
- A pipet is used to transfer 6.00 mLmL of a 3.75 MM stock solution in flask “S” to a 25.00-mL volumetric flask “A,” which is then diluted with DI H2OH2O to the calibration mark. The solution is thoroughly mixed. Next, 10.00 mLmL of the solution in volumetric flask “A” is transferred by pipet to a 50.00-mL volumetric flask “B” and then diluted with DI H2OH2O to the calibration mark. Calculate the molarity of the solution in volumetric flask “B.”A stock solution of potassium permanganate (KMn04) was prepared by dissolving 13.0g KMn04 with DI in a 100ml volumetric flask and diluting to the calibration mark. Determine the molarity of the solution.1. A 4.59 mL sample of HCl, specific gravity 1.3, required 50.5 mL of 0.9544N NaOH in a titration. Calculate the %w/w HCl. 2. A 10 mL sample of sulfuric acid solution required 16.85 mL of NaOH solution in a titration. Each mL of the NaOH solution was equivalent to 0.2477 g of potassium hydrogen phthalate. Calculate the sulfuric acid content in %w/v. MW of sulfuric acid, 98; MW of potassium hydrogen phtalate(KHC8H4O4 ) = 204.22
- Six 50.0 ml volumetric flask 1 through 6 are labeled. 10.00 ml of 2.00 x 10-1 M Fe(NO3)3 solution was then pipet into each volumetric flask. A 1.00,2.00,3.00,4.00 and 5.00ml of 2.00 x 10-3M NaSCN solution was then pipetted to flask 2 through 6 respectively. A sufficient amount of 0.10 M nitric acid was then added to each flask to make each a total volume of 50.00ml. Hint M1V1=M2V2 a)what would be the concentration of Fe(NO3)3 in 0.10M HNO3? b)what would be the concentration of NaSCN in 0.10M HNO3?In this problem I thought of using v/n=v/n or mv=mv, but neither get the correct answer. mv=mv yields 1.4 and v/n=v/n yields 0.4. Am I doing these calculations wrong, or am I doing the wrong type of calculation in the first place?Potassium acid phthalate, KHC8H4O4 ( MM=204.2 ), reacts with sodium hydroxide on a 1:1 molar basis. A sample of the acid weighing 0.4823 g was titrated with NaOH, requiring 24.35 mL to reach the endpoint. Calculate the molar concentration of the sodium hydroxide solution.