A diprotic acid, H,A, has K1 - 1.41 x 10 and K2 - 3.09 x 10%. If 50.00 mL. of 0.113 M H2A is placed in an flask and is titrated with 0.289 M N2OH. (a) What volume of NAOH would be needed to reach the second equivalence point? (b) What is the pH at the second half-equivalence point? (c) what would be the pH when 24.5 mt of base has been added to the flask?

Chemistry: Principles and Reactions
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Author:William L. Masterton, Cecile N. Hurley
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Chapter14: Equilibria In Acid-base Solutions
Section: Chapter Questions
Problem 74QAP: Fifty cm3 of 1.000 M nitrous acid is titrated with 0.850 M NaOH. What is the pH of the solution (a)...
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A diprotic acid, HzA, has K1 = 1.41 x 10 and K2 = 3.09 x 10.
If 50.00 mL. of 0.113 M H2A is placed in an flask and is titrated with 0.289 M N2OH.
(a) What volume of NAOH would be needed to reach the second equivalence point?
(b) What is the pH at the second half-equivalence point?
(c) what would be the pH when 24.5 ml. of base has been added to the flask?
Transcribed Image Text:A diprotic acid, HzA, has K1 = 1.41 x 10 and K2 = 3.09 x 10. If 50.00 mL. of 0.113 M H2A is placed in an flask and is titrated with 0.289 M N2OH. (a) What volume of NAOH would be needed to reach the second equivalence point? (b) What is the pH at the second half-equivalence point? (c) what would be the pH when 24.5 ml. of base has been added to the flask?
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