A disk of radius 30.0 cm is free to turn about an axle perpendicular to it through its center. It has very thin but strong string wrapped around its rim, and the string is attached to a ball that is pulled tangentially away from the rim of the disk (Figure 1). The pull increases in magnitude and produces an acceleration of the ball that obeys the equation a (t) = At, where t is in seconds and A is a constant. The cylinder starts from rest, and at the end of the third second, the ball's acceleration is 2.30 m/s? Part A Find A Express your answer in meters per second cubed. VO AEO ? A = 0.5 m/s3 Submit Previous Answers Request Answer igure < 1 of 1> X Incorrect; Try Again; 5 attempts remaining Ball Part B Pull Express the angular acceleration of the disk as a function of time, Express your answer in radians per second cubed multiplied by t. Disk a(t) = (rad/s )t

College Physics
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Chapter8: Rotational Equilibrium And Rotational Dynamics
Section: Chapter Questions
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Problem 9.61
A disk of radius 30.0 cm is free to turn about an axle perpendicular to
it through its center. It has very thin but strong string wrapped around
its rim, and the string is attached to a ball that is pulled tangentially
away from the rim of the disk (Figure 1). The pull increases in
magnitude and produces an acceleration of the ball that obeys the
equation a (t) = At, where t is in seconds and A is a constant. The
Part A
cylinder starts from rest, and at the end of the third second, the ball's
Find A.
acceleration is 2.30 m/s?.
Express your answer in meters per second cubed.
?
A = 0.5
m/s³
Submit
Previous Answers Request Answer
Figure
< 1 of 1
X Incorrect; Try Again; 5 attempts remaining
Ball
Part B
Pull
Express the angular acceleration of the disk as a function of time.
Express your answer in radians per second cubed multiplied by t.
Disk
a(t) =
(rad/s³)t
Transcribed Image Text:Problem 9.61 A disk of radius 30.0 cm is free to turn about an axle perpendicular to it through its center. It has very thin but strong string wrapped around its rim, and the string is attached to a ball that is pulled tangentially away from the rim of the disk (Figure 1). The pull increases in magnitude and produces an acceleration of the ball that obeys the equation a (t) = At, where t is in seconds and A is a constant. The Part A cylinder starts from rest, and at the end of the third second, the ball's Find A. acceleration is 2.30 m/s?. Express your answer in meters per second cubed. ? A = 0.5 m/s³ Submit Previous Answers Request Answer Figure < 1 of 1 X Incorrect; Try Again; 5 attempts remaining Ball Part B Pull Express the angular acceleration of the disk as a function of time. Express your answer in radians per second cubed multiplied by t. Disk a(t) = (rad/s³)t
Part C
How much time after the disk has begun to turn does it reach an angular speed of 12.5 rad/s?
Express your answer in seconds.
t =
Submit
Request Answer
Part D
Through what angle has the disk turned just as it reaches 12.5 rad/s? (Hint: See Section 2.6 in the textbook.)
Express your answer in radians.
0 - 00 =
rad
Submit
Request Answer
Transcribed Image Text:Part C How much time after the disk has begun to turn does it reach an angular speed of 12.5 rad/s? Express your answer in seconds. t = Submit Request Answer Part D Through what angle has the disk turned just as it reaches 12.5 rad/s? (Hint: See Section 2.6 in the textbook.) Express your answer in radians. 0 - 00 = rad Submit Request Answer
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