A force F =(4xi+3y N acts on an object as it moves in the x direction from the origin to x= 4m. The work done on the object by the force is Select one: O a. 42 J O b. 32 J Oc. 50 J Od. 28 )

Q: Find the work done by a force F = 1.80 î+2.20 ↑ N as it acts on an object %3D moving from the origin…

A: Given data:  Force F→ =1.80 i^+2.20 j^ N Displacement d→ =56.0 i^+31.0 j^ m  Required: Work done

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A: a) Work done is,

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Q: (-4) 2.0 How much work does the force F(æ) N do on a particle as it moves from x = 2 m to x = 9 m? W

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Q: solve number 22 with full steps and works

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Q: What work is done by a force F = (2x N)i+(3N)j, with x in meters, that moves -(4m)i – (3m)j ? %3D a…

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Q: A force F=(4xi +3y N acts on an object as it moves in the x direction from the origin to x= 4m. The…

A: Given data The force equation is given as F→=4xi^+3yj^ N. The object moves from origin to x = 4 m.…

Q: Q1 : A force F = ( 8i + 3j) N acts on aparticle that interrogees a displacement d = (2i + 2j )m A -…

A: It is given that, F→=8i+3j  Nd→=2i+2j  m

Q: 1. A particle was subjected to a force F, that varies with position as described by 375 F = where F…

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Q: 5) A force É = 12 Ni - 10 N j acts on an object. How much work does this force do as the object…

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A: Answer Given data Force F =(6xi + 4yj) The object moves in the x direction work W = ∫F • dr No work…

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Q: A force ~F=(6x5 N)i + (2y N)j acts between (x1,y1)= (2m, 3 m) to (x2; y2)=(3 m, 0 m).Calculate the…

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A: This can be solved using the basic definition of work. Refer next step for the solution.

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A: The work done is given by the expression,

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A: Given- Fx = 14x - 3x2 N x moves from, x = -1 m to x = 2 m,

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Q: 6) A 0.315-kg particle moves from an initial position 7, = 2.00 î – 1.00 ĵ + 3.00 k m to a final…

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Q: 9. A particle is subject to a force F, that varies with position V as shown in Figure P7.9. Find the…

A: Work done is equal to area under force Vs displacement curve.Part A :Work done from x = 0 to x = 5

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A: Answer is uploaded in 2nd step

Q: The force F(x,y) = [(2.56 N/m)y]i + [(3.14 N/m)x]j acts on a particle.  What is the work done, in…

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Q: A force F = (3.0N)i + cj acts on a particle as the particle goes through displacement d = (3.0m)î –…

A: The work done is given by  W = F→.d→ where, d is the displacement vector and F is the force vector.

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A: The above problem can be solved as follows

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A: Given  mass m= 3kg  Fx, force acting in x direction. gravitational force act on mass = m*g

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A: Given Mass m = 3.0 kg Scale of y axis Fs = 10.5 N Total distance travelled x = 20 m

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Q: JA 4.0 kg object moves a distance of 7.9 m under the E How much work is done by the force? action of…

A: Given data: Mass (m) = 4.0 kg Displacement (d) = 7.9 m Force (F) = 5.6 N Required: Work done (W)

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Q: A box weighs 49 N is pulled 6.0 m up along a 37° inclined plane. What is the work done by the…

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Q: A force F acts in the x-direction, its magnitude given by F = ax2, where x is in meters and a = 5.0…

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