A force →F=(1.70N)ˆi+(5.70N)ˆj+(7.80N)ˆk acts on a 5.50 kg mobile object that moves from an initial position of →di=(7.50m)ˆi+(9.10m)ˆj+(8.80m)ˆk to a final position of →df=(4.90m)ˆi+(6.00m)ˆj+(9.40m)ˆk in 2.90 s. Find (a) the work done on the object by the force in the 2.90 s interval, (b) the average power due to the force during that interval, and (c) the angle between vectors →di and →df.

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