A galvanic cell at a temperature of 25.0 °C is powered by the following redox reaction:2MNO (aq)+16H (aq)+5Pb (s) 2Mn (aq)+8H,O ()+5Pb (ag)+2+Suppose the cell is prepared with 3.07 MMnO and 3.11 MH in one half-cell and 2.83 MMn2+and 2.68 M Pb2+in the other.4Calculate the cell voltage under these conditions. Round your answer to 3 significant digits.x10?ExplanationCheck2019 McGraw-Hill Education. AovOX

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Asked Nov 24, 2019
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Calculate the cell voltage under these conditions around your hands to three significant digits please round only for the final answer. 

A galvanic cell at a temperature of 25.0 °C is powered by the following redox reaction:
2MNO (aq)+16H (aq)+5Pb (s) 2Mn (aq)+8H,O ()+5Pb (ag)
+
2+
Suppose the cell is prepared with 3.07 MMnO and 3.11 MH in one half-cell and 2.83 MMn
2+
and 2.68 M Pb
2+
in the other.
4
Calculate the cell voltage under these conditions. Round your answer to 3 significant digits.
x10
?
Explanation
Check
2019 McGraw-Hill Education. A
ovO
X
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A galvanic cell at a temperature of 25.0 °C is powered by the following redox reaction: 2MNO (aq)+16H (aq)+5Pb (s) 2Mn (aq)+8H,O ()+5Pb (ag) + 2+ Suppose the cell is prepared with 3.07 MMnO and 3.11 MH in one half-cell and 2.83 MMn 2+ and 2.68 M Pb 2+ in the other. 4 Calculate the cell voltage under these conditions. Round your answer to 3 significant digits. x10 ? Explanation Check 2019 McGraw-Hill Education. A ovO X

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Expert Answer

Step 1

The two half cell reactionsand their standard reduction potentials are given below.

MnO 4 - (aq) + 8H + (aq) + 5e - → Mn2+(aq) + 4H2O(l)        Eo= -0.13 V

Pb2+(aq) + 2e - → Pb(s)                                                          Eo= 1.51 V

 

Eocell = Eored – ...

E
Е Е-
-Е
cell
red
оxid
-+1.51V-(0.13V)
=1.64V
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E Е Е- -Е cell red оxid -+1.51V-(0.13V) =1.64V

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