A gas of unknown molecular mass was allowed to effusethrough a small opening under constant-pressure conditions.It required 105 s for 1.0 L of the gas to effuse. Underidentical experimental conditions it required 31 s for 1.0 Lof O2 gas to effuse. Calculate the molar mass of theunknown gas. (Remember that the faster the rate of effusion,the shorter the time required for effusion of 1.0 L; inother words, rate is the amount that diffuses over the timeit takes to diffuse.)

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Chapter5: Gases
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Problem 152CP: You have an equimolar mixture of the gases SO2 and O2, along with some He, in a container fitted...
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A gas of unknown molecular mass was allowed to effuse
through a small opening under constant-pressure conditions.
It required 105 s for 1.0 L of the gas to effuse. Under
identical experimental conditions it required 31 s for 1.0 L
of O2 gas to effuse. Calculate the molar mass of theunknown gas. (Remember that the faster the rate of effusion,
the shorter the time required for effusion of 1.0 L; in
other words, rate is the amount that diffuses over the time
it takes to diffuse.)

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