Question

Asked Oct 30, 2019

A genetic experiment involving peas yielded one sample of offspring consisting of 455 green peas and 176 yellow peas. Use a 0.05 significance level to test the claim that under the same circumstances, 24 % of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution.

Step 1

**State the appropriate hypothesis:**

Let *p* be the population proportion of yellow offspring peas.

The given claim is that, the percentage of yellow offspring peas is equal to 24%.

That is, *p* = 0.24.

The researcher’s objective is to test, whether or not the proportion of yellow offspring peas is equal to 0.24.

Step 2

*The hypotheses are given below:*

*Null hypothesis:*

*H*_{0} : *p* = 0.24

That is, the proportion of yellow offspring peas is equal to 0.24.

*Alternative hypothesis:*

*H*_{a} : *p *≠ 0.24 (Two tailed test)

That is, the proportion of yellow offspring peas is not equal to 0.24.

**Obtain the sample proportion:**

It is given that among a sample of 631 (=455 + 176) offspring peas, 176 offspring peas are yellow in color.

The sample proportion of yellow offspring peas is obtained as **0.2789 **(=176/631).

**Obtain the test statistic value:**

The test statistic value is obtained as follows:

Step 3

p-value:

In this case, the test is two tailed. ...

Tagged in

Q: Sam computed a 90% confidence interval for μ from a specific random sample of size n. He claims that...

A: Sam computed a 90% confidence interval for µ from a specific random sample of size n.

Q: Please show TI 84 steps. We don't use standardized table for z score

A: Introduction:According to the Central Limit Theorem, if the sampling distribution of the sample prop...

Q: What does it mean for a regression line to be the "best-fit" line.

A: The form of the simple linear regression line is given by,

Q: explain please General definition and properties of continuous random variables and their probabilit...

A: A fundamental difference separates discrete and continuous random variables in terms of how probabil...

Q: Assume the random variable X is normally distributed, with mean u 58 and standard deviation o 4. Fin...

A: The z-score for the 12th percentile is the value such that 12% of the area under the standard normal...

Q: Part D and E

A: In order to get the test statistic value, the MINITAB output for the paired t-test is given below.

Q: In a study of the accuracy of fast food drive-through orders, Restaurant A had 241 accurate orders ...

A: The formula for the 95% confidence interval for the proportion is given below:

Q: The random variable x is known to be uniformly distributed between 1.0 and 1.5. Compute P(1.20 <...

A: From the given information,The random variable ‘X’ is uniformly distributed with the interval (1.0, ...

Q: Part A, B, D

A: Part (a):The term, μi represents the random error term in the regression model, for the ith observat...