In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6993 subjects randomly selected from an online group involved with ears. There were 1308 surveys returned. Use a 0.01 significance level totest the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution.Identify the null hypothesis and alternative hypothesis.В. Но: р3D0.2А. Но: р3D0.2H1:p>0.2H1:p 0.2Е. Но: р

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Asked Dec 8, 2019
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In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6993 subjects randomly selected from an online group involved with ears. There were 1308 surveys returned. Use a 0.01 significance level to
test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution.
Identify the null hypothesis and alternative hypothesis.
В. Но: р3D0.2
А. Но: р3D0.2
H1:p>0.2
H1:p<0.2
С. Но: р#0.2
O D. Ho: p= 0.2
H4:p=0.2
H1: p#0.2
O F. Но: р> 0.2
Е. Но: р<0.2
H4:p=0.2
H4:p=0.2
The test statistic is z =
(Round to two decimal places as needed.)
The P-value is
(Round to three decimal places as needed.)
Because the P-value is
the significance level,
the null hypothesis. There is
evidence to support the claim that the return rate is less than 20%.
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In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6993 subjects randomly selected from an online group involved with ears. There were 1308 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. В. Но: р3D0.2 А. Но: р3D0.2 H1:p>0.2 H1:p<0.2 С. Но: р#0.2 O D. Ho: p= 0.2 H4:p=0.2 H1: p#0.2 O F. Но: р> 0.2 Е. Но: р<0.2 H4:p=0.2 H4:p=0.2 The test statistic is z = (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) Because the P-value is the significance level, the null hypothesis. There is evidence to support the claim that the return rate is less than 20%.

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Expert Answer

Step 1

From the given information, the claim of the problem is the return rate is less than 20%.

 

Null hypothesis:

 

H0p=0.2.

 

That is, there is no significance evidence that the return rate is less than 20%.

 

Alternative hypothesis:

 

H1p<0.2.

 

That is, there is a significance evidence that the return rate is less than 20%.

 

The correct option is B. H0p=0.2 and H1p<0.2.

 

From the given information, in a sample of 6993 respondents, 1308 of them are returned.

 

The sample size is, n =6993 and x=1308. The sample proportion is   =0.19(=1308/6993)

 

The test statistic is  ̶ 2.08 and it is calculated below

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p- p p(1- p) 2test 0.19- 0.20 0.20(1– 0.20) 6993 -0.01 0.0048 = -2.08

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Step 2

The P-value is 0.019 and it is calcula...

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P-value = P(z < Z,est ) [Since, Given Hypothesis is Left tail test] =P(z <-2.08) [By Excel functi on =0.019 =NORM.DIST(- 2.08,0,1,TRUE)

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