In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6993 subjects randomly selected from an online group involved with ears. There were 1308 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. В. Но: р3D0.2 А. Но: р3D0.2 H1:p>0.2 H1:p<0.2 С. Но: р#0.2 O D. Ho: p= 0.2 H4:p=0.2 H1: p#0.2 O F. Но: р> 0.2 Е. Но: р<0.2 H4:p=0.2 H4:p=0.2 The test statistic is z = (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) Because the P-value is the significance level, the null hypothesis. There is evidence to support the claim that the return rate is less than 20%.

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In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6993 subjects randomly selected from an online group involved with ears. There were 1308 surveys returned. Use a 0.01 significance level to
test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution.
Identify the null hypothesis and alternative hypothesis.
В. Но: р3D0.2
А. Но: р3D0.2
H1:p>0.2
H1:p<0.2
С. Но: р#0.2
O D. Ho: p= 0.2
H4:p=0.2
H1: p#0.2
O F. Но: р> 0.2
Е. Но: р<0.2
H4:p=0.2
H4:p=0.2
The test statistic is z =
(Round to two decimal places as needed.)
The P-value is
(Round to three decimal places as needed.)
Because the P-value is
the significance level,
the null hypothesis. There is
evidence to support the claim that the return rate is less than 20%.
Transcribed Image Text:In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6993 subjects randomly selected from an online group involved with ears. There were 1308 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. В. Но: р3D0.2 А. Но: р3D0.2 H1:p>0.2 H1:p<0.2 С. Но: р#0.2 O D. Ho: p= 0.2 H4:p=0.2 H1: p#0.2 O F. Но: р> 0.2 Е. Но: р<0.2 H4:p=0.2 H4:p=0.2 The test statistic is z = (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) Because the P-value is the significance level, the null hypothesis. There is evidence to support the claim that the return rate is less than 20%.
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