=1ZKA genetic experiment with peas resulted in one sample of offspring that consisted of 422 green peas and 154 yellow peas.a. Construct a 90% confidence interval to estimate of the percentage of yellow peas.b. Based on the confidence interval, do the results of the experiment appear to contradict the expectation that 25% of the offspring peas would be yellow?Statcrunch720WS32,903a. Construct a 90% confidence interval. Express the percentages in decimal form.

From the provided information, Sample size (n) = 422 + 154 = 576 From which 154 yellow peas so…

Answered: A genetic experiment with peas resulted…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A genetic experiment with peas resulted in one sample of offspring that consisted of 423 green peas and 160 yellow peas. a. Construct a 90% confidence interval to estimate of the percentage of yellow peas. b. Based on the confidence interval, do the results of the experiment appear to contradict the expectation that 25% of the offspring peas would be yellow? Construct a 90% confidence interval. Express the percentages in decimal form. Based on the confidence interval, do the results of the experiment appear to contradict the expectation that 25% of the offspring peas would be yellow?
A genetic experiment with peas resulted in one sample of offspring that consisted of 442 green peas and 164 yellow peas. a. Construct a 90% confidence interval to estimate of the percentage of yellow peas. b. Based on the confidence interval, do the results of the experiment appear to contradict the expectation that 25% of the offspring peas would be yellow? a. Construct a 90% confidence interval. Express the percentages in decimal form. (
A genetic experiment with peas resulted in one sample of offspring that consisted of 445 green peas and 164 yellow peas. a. Construct a 95% confidence interval to estimate the percentage of yellow peas. b. Based on the confidence interval, do the results of the experiment appear to contradict the expectation that 25% of the offspring peas would be yellow?
A genetic experiment with peas resulted in one sample of offspring that consisted of 445 green peas and 159 yellow peas. A. Construct a 90% confidence interval to estimate the percentage of yellow peas B. It was expected that 25% of the offspring peas would be yellow. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations? Construct a 90% confidence interval. Express the percentages in decimal form. ___
A genetic experiment with peas resulted in one sample of offspring that consisted of 411 green peas and 153 yellow peas. a. Construct a 90% confidence interval to estimate of the percentage of yellow peas. b. Based on the confidence interval, do the results of the experiment appear to contradict the expectation that 25% of the offspring peas would be yellow?
A clinic measured the systolic blood pressure for a random sample of 10 patients. The resulting 95% confidence interval for the mean systolic blood pressure of all the patients at this clinic was (111.3, 129.5). What was the mean systolic blood pressure from the sample of 10 patients? 18.2 111.3 120.4 129.5
construct the 95% and 99% confidence intervals for the population proportion p using the indicated sample statistics. Which interval is wider? If convenient, use technology to construct the confidence intervals. 1) Charity In a survey of 2939 U.S. adults, 2439 say they have contributed to a charity in the past 12 months. 2) Eating Meat Of 458 U.S. adults surveyed, 224 eat meat daily. 3) Vacation In a survey of 1003 U.S. adults, 110 say they would go on vacation to Europe if cost did not matter.
Suppose that a random sample of 142 graduate-admissions personnel was asked what role scores on standardized tests (such as the GMAT or GRE) play in the consideration of a candidate for graduate school. Of these sample members, 87 answered “very important.” Find a 95% confidence interval for the population proportion of graduate admissions personnel with this view.
A statistician proposed a new method for constructing a 90 percent confidence interval to estimate the median ofassessed home values for homes in a large community. To test the method, the statistician will conduct a simulationby selecting 10,000 random samples of the same size from the population. For each sample, a confidence intervalwill be constructed using the new method. If the confidence level associated with the new method is actually 90percent, which of the following will be captured by approximately 9,000 of the confidence intervals constructedfrom the simulation?(A) The sample mean(B) The sample median(C) The sample standard deviation(D) The population mean(E) The population median
A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than examine the records for all students, the dean randomly selects 200 students and finds that 118 of them are receiving financial aid. Use a 90% confidence interval to estimate the true proportion of students on financial aid. Express the answer in the form ± E and round to the nearest thousandth. Group of answer choices
Out of 67,410 surgeries tracked in a study in the U.K., 2832 were followed by surgical site infections (Coello et al. 2005). a. What is a 95% confidence interval for the proportion of surgeries followed by surgical site infection in the U.K.? b. Assume that the data are a random sample.If the study had followed a total of only 674 surgeries from the same population, would the confidence interval have been wider or narrower?
The employee manager of a large company would like to estimate the proportion of full-time employees who prefer adopting plan A of two available health care plans in the forthcoming annual enrollment period. A survey of 1,000 randomly selected employees revealed that a 95% confidence interval for the proportion of employees preferring plan A is [14.7%, 19.3%]. Based on the confidence interval the manager can conclude (select one): Group of answer choices A.170 employees out of 1,000 preferred plan A on the survey. B.The proportion of employees preferring plan A is between 14.7% and 19.3% with 95% chance. C.The margin of error of the confidence interval is 4.6%. D.At least 147 employees out of 1000 prefer plan A on the survey.

SEE MORE QUESTIONS

Recommended textbooks for you

MATLAB: An Introduction with Applications

Statistics

ISBN:

9781119256830

Author:

Amos Gilat

Publisher:

John Wiley & Sons Inc

Probability and Statistics for Engineering and th…

Statistics

ISBN:

9781305251809

Author:

Jay L. Devore

Publisher:

Cengage Learning

Statistics for The Behavioral Sciences (MindTap C…

Statistics

ISBN:

9781305504912

Author:

Frederick J Gravetter, Larry B. Wallnau

Publisher:

Cengage Learning

MATLAB: An Introduction with Applications

Statistics

ISBN:

9781119256830

Author:

Amos Gilat

Publisher:

John Wiley & Sons Inc

Probability and Statistics for Engineering and th…

Statistics

ISBN:

9781305251809

Author:

Jay L. Devore

Publisher:

Cengage Learning

Statistics for The Behavioral Sciences (MindTap C…

Statistics

ISBN:

9781305504912

Author:

Frederick J Gravetter, Larry B. Wallnau

Publisher:

Cengage Learning

Elementary Statistics: Picturing the World (7th E…

Statistics

ISBN:

9780134683416

Author:

Ron Larson, Betsy Farber

Publisher:

PEARSON

The Basic Practice of Statistics

Statistics

ISBN:

9781319042578

Author:

David S. Moore, William I. Notz, Michael A. Fligner

Publisher:

W. H. Freeman

Introduction to the Practice of Statistics

Statistics

ISBN:

9781319013387

Author:

David S. Moore, George P. McCabe, Bruce A. Craig

Publisher:

W. H. Freeman

SEE MORE TEXTBOOKS