(a) Given Palmitic acid weight =112 g Palmitic acid Molecular weight = 256.4241 g/mol Volume of solvent(benzene) = 725 ml 1. Molarity of the solution =(Wt/M.Wt)x(1000/V in mL) = (112x1000)/(256.4241x725) = 0.602 moles/L
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- Over time, as their free fatty acid (FFA) content increases,edible fats and oils become rancid. To measure rancidity, the fator oil is dissolved in ethanol, and any FFA present is titrated withKOH dissolved in ethanol. In a series of tests on olive oil, a stocksolution of 0.050 Methanolic KOH was prepared at 25C, storedat 0C, and then placed in a 100-mL buret to titrate any oleic acid[CH₃(CH₂)₇CH=CH(CH₂)₇COOH] present in the oil. Each offour 10.00-g samples of oil took several minutes to titrate: thefirst required 19.60 mL, the second 19.80 mL, and the third and fourth 20.00 mL of the ethanolic KOH.(a) What is the apparent acidity of each sample, in terms of mass% of oleic acid? (Note:As the ethanolic KOH warms in the bu-ret, its volume increases by a factor of 0.00104/C.)(b) Is the variation in acidity a random or systematic error? Ex-plain.(c) What is the actual acidity? How would you demonstrate this?4. What volume of dilute nitric acid of density 1.11g/mL and 19% nitric acid by weight contains in 10g nitric acid. 5. Given 200cm3 of pure water at 40C, what volume of a solution of hydrochloric acid whose density is 1.175g/cm3 and containing 344.4% HCl by weight, could be prepared?6. How many grams of Na2CO3 are needed to prepare 500cm3 of a solution containing 10.0mg of CO32- per cm3?7. What volume of 0.300M H2SO4 is required to exactly neutralize 200mL of 0.500M NaOH?2NaOH + H2SO4 Na2SO4 + 2H2OGIVEN: - 500mg of ascorbic acid - 2L of distilled water - 7.5% m/v (this is the stock solution) To answer: 1. Give a solution to get the given stock solution. 2. Give a full solution when it will be diluted to 5.9% and the volume is 75mL MAKE SURE THAT WHEN THE REQUIRED STOCK SOLUTION IN ML AND REQUIRED ML IN THE DILUTION WILL TOTAL TO THE NEW VOLUME WHICH IS 75mL (ALSO GIVE A DETAILED COMPUTATION, THANK YOU!)
- . How many ml of water do you add to 10ml of glycerol stock if you want to dilute it by a factorof a) 3, b) 4, c) 10, d) 100? Hint: first calculate v(d-n), then v(water) = v(d-n) – v(stock)6. You have a 0.5M stock solution of NaCI (Formula Weight: 58.4g/mole), a 250mM stock solution of glucose (Formula Weight; 180.2g/mole), and a bottle of solid Tris base Formula Weight: 121.1g/mole). How would prepare (be specific) 250mL of a single solution containing 150mM Tris, 0.025M glucose, and 50mM NaCI.The solubility of compound B is 59 g per 100 mL in boiling methanol and 30 g per 100 g in cold methanol, while its solubility in water is 7.2 g per 100 mL at 95oC and 0.22 g per 100 mL at 20oC. What solvent would be better for recrystallization of the compound? Explain
- What weight of HCl is present in 30mL of hydrochloric acid of specific gravity 1.19 and contains 37.5% by weight of HCl?A 0.9000-g of KIO3 is dissolved in 500-mL distilled water. A 50.0-mL aliquot portion was run down into an Erlenmeyer flask and 2-g of KI and 2-mL of 6M HCl were added to it. Directly after, the solution was titrated with a 24.80-mL Na2S2O3 solution to a faint yellow solution. Starch TS was added to the resulting solution and the titration with the Na2S2O3 solution continued wherein an additional 1.33-mL was required to bring the blue color of the solution to disappear completely. MW: KIO3 = 214.0 g/mol ; Na2S2O3 = 158.1 g/mol Compute the N of the Na2S2O3 solution. None of the choices 0.09657 N 0.1075 N 0.1017 Nis Cyclohexane soluble in CH2Cl2, water, NaOH, or H2SO4?
- At an air-water interface, fatty acids such as oleic acid liein a one-molecule-thick layer (monolayer), with the heads in thewater and the tails perpendicular in the air. When 2.50 mg of oleic acid is placed on a water surface, it forms a circular mono-layer 38.6 cm in diameter. Find the surface area (in cm²) occu-pied by one molecule (of oleic acid M=283 g/mol).In a solution containing 25ml (NH4)2S2O8 with a total volume = 100 ml =0.1 liters , the solution composition are shown below.Note; the solution require 25ml of 0.2M S2O8^-2.SOLUTION Kl KNO3 EDTA Na2S2O3 STARCH50ml 23ml 1 drop 1 ml 10 dropsExperiment; initial (S2O8-2) =0.05M ; INITIAL (l-)=0.10 Mml of S2O3^-2 added Time in minutes and seconds for color change Cumulative time in seconds Total moles of S2O8^-2 consumed1 1:43 2.0 x 10^-42 1:20 4.0 x 10^-43 1:13 6.0 x 10 ^-44 1.17 8.0 x 10 ^-45 1.24 10 x 10 ^-41a) Find the cumulative time in secondsb) for the runs ,plot mole of S2O8^2- REACTION vs. time in seconds2) Draw a straight line through ( origin ) the points and calculate the slope3) divide the value of the slope by the total volume of ( 0.1 L) to get the rate in units of M/s4) find the rate5 )calculate x and y and kWhat is the concentration in units of grams of dye per liter of solution ,of the dilute dye solution that is produced as follows? transfer 19.53 ml of stick solution (6.10g/L) to a 200.0Ml volumetric flask and dilute to the 200 ml line with deionized water. Correct number of significant figs