(a) Given the formula, F=qv⃗ ×B⃗ =qvBsinθF=qv→×B→=qvBsinθ, the magnetic force on a moving charged particle is always perpendicular to the magnetic field. It therefore follows that the trajectory of a moving charge is also always perpendicular to the magnetic field lines.   (b) The magnetic force acting on a charged particle can never do work because at every instant the force is perpendicular to the velocity.

Physics for Scientists and Engineers, Technology Update (No access codes included)
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Chapter29: Magnetic Fields
Section: Chapter Questions
Problem 29.2OQ: Rank the magnitudes of' the forces exerted on the following particles from largest to smallest. In...
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(a) Given the formula, F=qv⃗ ×B⃗ =qvBsinθF=qv→×B→=qvBsinθ, the magnetic force on a moving charged particle is always perpendicular to the magnetic field. It therefore follows that the trajectory of a moving charge is also always perpendicular to the magnetic field lines. 

 (b) The magnetic force acting on a charged particle can never do work because at every instant the force is perpendicular to the velocity.

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