A hobbyist launches a projectile from ground level on a horizontal plain. It reaches a maximum height of 72.3 m and lands 111 m from the launch point, with no appreciable air resistance. What was the angle of launch if g = 9.80 m/s2? Hint: Such a wonderful problem. It's a golf shot type problem and you have been given the Range and the maximum Height. Write the two golf shot equations for these quantities and form a ratio of the two. The initial velocity and gravitational acceleration will divide out of the ratio. You will be left with an equation in nothing but trigonometric functions. Use these identities and you will wind up with an expression for the tangent of the launch angle: sin(20) = 2 sin 0 cos 0 sin? 0 = (sin 0)? O 67.4° O 44.8° O 22.6°

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Chapter1: Units, Trigonometry. And Vectors
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A hobbyist launches a projectile from ground level on a horizontal plain. It reaches a maximum height of 72.3 m and lands 111 m from the launch point, with no
appreciable air resistance. What was the angle of launch if g = 9.80 m/s2?
Hint: Such a wonderful problem. It's a golf shot type problem and you have been given the Range and the maximum Height. Write the two golf shot equations for these
quantities and form a ratio of the two. The initial velocity and gravitational acceleration will divide out of the ratio. You will be left with an equation in nothing but
trigonometric functions. Use these identities and you will wind up with an expression for the tangent of the launch angle:
sin(20) = 2 sin 0 cos 0
sin? 0 = (sin 0)?
O 67.4°
44.8°
O 22.6°
O 69.0°
Transcribed Image Text:A hobbyist launches a projectile from ground level on a horizontal plain. It reaches a maximum height of 72.3 m and lands 111 m from the launch point, with no appreciable air resistance. What was the angle of launch if g = 9.80 m/s2? Hint: Such a wonderful problem. It's a golf shot type problem and you have been given the Range and the maximum Height. Write the two golf shot equations for these quantities and form a ratio of the two. The initial velocity and gravitational acceleration will divide out of the ratio. You will be left with an equation in nothing but trigonometric functions. Use these identities and you will wind up with an expression for the tangent of the launch angle: sin(20) = 2 sin 0 cos 0 sin? 0 = (sin 0)? O 67.4° 44.8° O 22.6° O 69.0°
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