A lab tech builds a circuit as shown in the figure. Find the following. (Assume C₁ = 33.0 μF and C₂ = 2.93 µF.) 6.00 uF C₁ µF C₂ µF 9.00 V (a) the equivalent capacitance (in µF) 5.79 HF 6.00 μF capacitor (b) the charge on each capacitor (in μC) C₂ (left) C₂ (right) C₂ C₁ µF ✓ HC ✓ HC 52.11 52.11 26.37 Note that the charge on each capacitor in the series is the same as the charge on the equivalent capacitor. Apply the relationship Q = CAV to find the charge. For the two capacitors in parallel, you will first need to determine the potential difference across the parallel combination, then calculate the charges on the individual capacitors. μC 52.11 x Note that the charge on each capacitor in the series is the same as the charge on the equivalent capacitor. Apply the relationship Q = CAV to find the charge. For the two capacitors in parallel, you will first need to determine the potential difference across the parallel combination, then calculate the charges on the individual capacitors. μC (c) the potential difference across each capacitor (in V) C₂ (left) C₂ (right) C₂ 6.00 uF capacitor V V V V

A lab tech builds a circuit as shown in the figure. Find the following. (Assume C₁ = 33.0 μF and C₂ = 2.93 µF.) 6.00 uF C₁ µF C₂ µF 9.00 V (a) the equivalent capacitance (in µF) 5.79 HF 6.00 μF capacitor (b) the charge on each capacitor (in μC) C₂ (left) C₂ (right) C₂ C₁ µF ✓ HC ✓ HC 52.11 52.11 26.37 Note that the charge on each capacitor in the series is the same as the charge on the equivalent capacitor. Apply the relationship Q = CAV to find the charge. For the two capacitors in parallel, you will first need to determine the potential difference across the parallel combination, then calculate the charges on the individual capacitors. μC 52.11 x Note that the charge on each capacitor in the series is the same as the charge on the equivalent capacitor. Apply the relationship Q = CAV to find the charge. For the two capacitors in parallel, you will first need to determine the potential difference across the parallel combination, then calculate the charges on the individual capacitors. μC (c) the potential difference across each capacitor (in V) C₂ (left) C₂ (right) C₂ 6.00 uF capacitor V V V V

College Physics

10th Edition

ISBN:9781285737027

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter16: Electrical Energy And Capacitance

Section: Chapter Questions

Problem 50P: Two capacitors, C1 = 18.0 F and C2 = 36.0 F, are connected in series, and a 12.0-V battery is...

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