A lab technician is tested for her consistency by making multiple measurements of the cholesterol level in one blood sample. The target precision is a standard deviation of 1 mg/dL or less. If 18 measurements are taken and the standard deviation is 2 mg/dL, is there enough evidence to support the claim that her standard deviation is greater than the target, at a = .01? Yes, since the x2 test value 68.000 is greater than the critical value 33.409.

A lab technician is tested for her consistency by making multiple measurements of the cholesterol level in one blood sample. The target precision is a standard deviation of 1 mg/dL or less. If 18 measurements are taken and the standard deviation is 2 mg/dL, is there enough evidence to support the claim that her standard deviation is greater than the target, at a = .01? Yes, since the x2 test value 68.000 is greater than the critical value 33.409.

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Description: A lab technician is tested for her consistency by making multiplemeasurements of the cholesterol level in one blood sample. The targetprecision is a standard deviation of 1 mg/dL or less. If 18 measurements aretaken and the standard deviation is 2 m

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Topic Video

Question

A lab technician is tested for her consistency by making multiple
measurements of the cholesterol level in one blood sample. The target
precision is a standard deviation of 1 mg/dL or less. If 18 measurements are
taken and the standard deviation is 2 mg/dL, is there enough evidence to
support the claim that her standard deviation is greater than the target, at a
= .01?
%3D
Yes, since the x2 test value 68.000 is greater than the critical value 33.409.
Yes, since the x2 test value 68.000 is greater than the critical value 34.805.
No, since the x2 test value 34.00 is greater than the critical value 33.409.
No, since the x2 test value 34.00 is less than the critical value 34.805.

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