A lens maker is creating eyeglasses for a farsighted patient, whose near point is 100 cm. The lens maker is using a mold that fixes the front radius of curvature of the lens to be 2 cm. If the index of refraction of the lens is 1.5 and patient's desired near point is 15 cm, to what radius of curvature in centimeters must the lens maker must grind the back surface of the lens?

A lens maker is creating eyeglasses for a farsighted patient, whose near point is 100 cm. The lens maker is using a mold that fixes the front radius of curvature of the lens to be 2 cm. If the index of refraction of the lens is 1.5 and patient's desired near point is 15 cm, to what radius of curvature in centimeters must the lens maker must grind the back surface of the lens?

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter26: Image Formation By Mirrors And Lenses

Section: Chapter Questions

Problem 6CQ

See similar textbooks

Similar questions

What is the magnification of a magnifying lens with a focal length of 10 cm if it is held 3.0 cm from the eye and the object is 12 cm from the eye?
A lamp of height S cm is placed 40 cm in front of a converging lens of focal length 20 cm. There is a plane mirror 15 cm behind the lens. Where would you find the image when you look in the mirror?
An object viewed with the naked eye subtends a 2° angle. If you view the object through a 10 x magnifying glass, what angle is subtended by the image formed on your retina?
A convex mirror with a radius of curvature of 25.0 cm is used to form an image of an arrow that is 10.0 cm away from the mirror. If the arrow is 2.00 cm tall and inverted (pointing below the optical axis), what is the height of the arrows image?
It has become common to replace the cataract-clouded lens of the eye with an internal lens. This intraocular lens can be chosen so that the person has perfect distant vision. Will the person be able to read without glasses? If the person was nearsighted, is the power of the intraocular lens greater or less than the removed lens?
The magnification of an upright image that is 34.0 cm away from its object is 0.400. What type of lens is used to form the image, and what is its focal length?
Show that the magnification of a thin lens is given by M = di/do (Eq. 38.6). Hint: Follow the derivation of the lens makers equation (page 1233) and start with a thick lens.
A 7.5x binocular produces an angular magnification of 7.50, acting like a telescope. (Mirrors are used to make the image upright.) If the binoculars have objective lenses with a 75.0 cm focal length, what is the focal length of the eyepiece lenses?
A point source of light is 50 cm in front of a converging lens of focal length 30 cm. A concave mirror with a focal length of 20 cm is placed 25 cm behind the lens. Where does the final image form, and what are its orientation and magnification?
How far should you hold a 2.1 cm-focal length magnifying glass from an object to obtain a magnification of 10 x ? Assume you place your eye 5.0 cm from the magnifying glass.
A converging lens has a focal length of 10.0 cm. Locate the object if a real image is located at a distance from the lens of (a) 20.0 cm and (b) 50.0 cm. What If? Redo the calculations if the images are virtual and located at a distance from the lens of (c) 20.0 cm and (d) 50.0 cm.
Under what circumstances will an image be located at the focal point of a spherical lens or mirror?