A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire.Let us first derive the expression for the tension.By Newton's First LawΣF = the components of force that makes this so isΣF = T - = 0Simplifying this results toT = g/(ϕ)Analyzing the figure above, we arrive at(ϕ) = sqrt( 2 + ) / ( / + )By substitution, we arrive at the following:T = ( + 2 ) g / ( sqrt ( 2 + ) )If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal toT = 0.370 N Solutiona)Let us first derive the expression for the tension.By Newton's First LawEF = 0the components of force that makes this so isIF = T costetha= 0mgSimplifying this results toT= mg/ cosAnalyzing the figure above, we arrive at(4) = sqrt(+cosBy substitution, we arrive at the following:T= m+ 2sqrt (2+))If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal toT=0.370 N2.+ A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find thetension in the wire.Ld

Using Newton's law, ∑F=0 From the above expressions, Tcosϕ-mg=0 Simplifying this results to T=mgcosϕ…

Answered: a) Let us first derive the expression…

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter12: Static Equilibrium And Elasticity

Section: Chapter Questions

Problem 56P: Alarge uniform cylindrical steel rod of density =7.8g/cm3 is 2.0 m long and has a diameter of 5.0...

See similar textbooks

Related questions

Concept explainers

Question

100%

A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire.

Let us first derive the expression for the tension.

By Newton's First Law

ΣF =

the components of force that makes this so is

ΣF = T - = 0

Simplifying this results to

T = g/(ϕ)

Analyzing the figure above, we arrive at

(ϕ) = sqrt( ² + ) / ( / + )

By substitution, we arrive at the following:

T = ( + 2 ) g / ( sqrt ( ² + ) )

If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to

T = 0.370 N

Solution
a)
Let us first derive the expression for the tension.
By Newton's First Law
EF = 0
the components of force that makes this so is
IF = T costetha
= 0
mg
Simplifying this results to
T= m
g/ cos
Analyzing the figure above, we arrive at
(4) = sqrt(
+
cos
By substitution, we arrive at the following:
T= m
+ 2
sqrt (
2+
))
If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to
T=
0.370 N
2.
+

A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the
tension in the wire.
L
d

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 4 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions