A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. Solution a) Let us first derive the expression for the tension. By Newton's First Law ΣF = ______ the components of force that makes this so is ΣF = T ______ - ______ = 0 Simplifying this results to T = ______g/______(ϕ) Analyzing the figure above, we arrive at ______(ϕ) = sqrt( ______2 +______ ) / (______ /______ +______ ) By substitution, we arrive at the following: T = ______ ( ______ + 2 ______ ) g / ( ______ sqrt ( ______2 + ______ ) ) If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to T = ______
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A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire.
Solution
a)
Let us first derive the expression for the tension.
By Newton's First Law
ΣF = ______
the components of force that makes this so is
ΣF = T ______ - ______ = 0
Simplifying this results to
T = ______g/______(ϕ)
Analyzing the figure above, we arrive at
______(ϕ) = sqrt( ______2 +______ ) / (______ /______ +______ )
By substitution, we arrive at the following:
T = ______ ( ______ + 2 ______ ) g / ( ______ sqrt ( ______2 + ______ ) )
If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to
T = ______
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