A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. d. Solution a) Let us first derive the expression for the tension. By Newton's First Law EF= the components of force that makes this so is EF -T Simplifying this results to T= g/ (0) Analyzing the figure above, we arrive at (4) = sqrt( 2. By substitution, we arrive at the following: T= +2 sqrt ( 2. )) If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to 0.370 N

A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. d. Solution a) Let us first derive the expression for the tension. By Newton's First Law EF= the components of force that makes this so is EF -T Simplifying this results to T= g/ (0) Analyzing the figure above, we arrive at (4) = sqrt( 2. By substitution, we arrive at the following: T= +2 sqrt ( 2. )) If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to 0.370 N

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter10: Rotational Motion

Section: Chapter Questions

Problem 33P: A 15.0-m uniform ladder weighing 500 N rests against a frictionless wall. The ladder makes a 60.0...

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QUESTION 1 Problem A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. Solution a) Let us first derive the expression for the tension. By Newton's First Law ΣF = ______ the components of force that makes this so is ΣF = T_____ -_____ = 0 Simplifying this results to T =________ g/_____(ϕ) Analyzing the figure above, we arrive at (ϕ) = sqrt(_____ 2 +______ ) / (_____ /_____ +_____ ) By substitution, we arrive at the following: T = (_____ + 2______ ) g / ( ______ sqrt (______ 2 +_____ ) ) If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to T = ________ 0.370 N
A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. Solution a) Let us first derive the expression for the tension. By Newton's First Law ΣF = ___ the components of force that makes this so is ΣF = T___ - ___ = 0 Simplifying this results to T = ___g/___(ϕ) Analyzing the figure above, we arrive at ___(ϕ) = sqrt(___2 + ___ ) / ( ___/___ + ___ ) By substitution, we arrive at the following: T = ___ ( ___ + 2___ ) g / ( ___sqrt ( ___2 + ___ ) ) If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to T = ___0.370 N