A liquid limits test carried out on a sample of inorganic soil taken from below the water table gave the following results: Determine the liquid limit, plastic limit and plasticity index of this soil.
Q: A cylindrical sample of soil has a height of 205mm and a diameter of 102.4mm. The sample was found…
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Q: The Atterberg limits of a clay soil are 72%, 40% and 23%. If a sample of this soil has a volume of…
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Q: A soil specimen weighs 30 grams oven dried. When mixed with 7.50 cc of water, the soil is at its…
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Q: The following data were obtained from the Atterberg Limits test for a soil: Liquid Limit 41.0 %…
A: Given that, Liquid limit= WL= 41% Plastic limit= Wp= 21.1% Natural water content= w= 30% To find:-…
Q: Atterberg Limit From the laboratory results of the Atterberg Limit Test, the Liquid Limit of the…
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Q: 2) A moist sample was found to have a volume of 22.3 cubic centimeters and to weigh 29.7 grams. The…
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Q: Question 15 The results of the particle-size analysis of a soil are as follows: • Percent passing…
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Q: A soil sample has a volume of 0.07 ft*3 and a total weight of 9.10 Ibs. After oven dried, the soil…
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Q: Civil Engineering A sample of soil with LL of 72.8 was found to have a liquidity index of 1.21 and…
A: Given data LL = 72.8 LI = 1.21 WC = 81.3
Q: From laboratory investigations, the liquid limit, plastic limit, natural moisture content and flow…
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Q: A 15 cm diameter and 7 cm long cylinder was used to collect soil sample. The fresh mass of the…
A: A soil sample length, diameter, fresh mass, moisture content, and particle density have been given…
Q: A sample of soil weighs 1.5N. Its clay fraction weighs 0.34N. If its liquid limit is 60% and its…
A: Given data Weight of soil is 1.5 N. Weight of clay fraction is 0.34 N. The liquid limit (wl) is 60…
Q: A soil sample having a liquidity index of 0.79, a plasticity index of 15 and a plastic limit of 13.…
A: solution we know Ip=15(plasticity index)plastic limit wp=13we know Ip = wL-wp15 = wL-13wL=28
Q: Given the laboratory results of the Atterberg Limit Test in Figure 3.1 ar Table 3.1. a. Determine…
A: As there are multiple questions posted, according to the guidelines, only the first three are being…
Q: PROBLEM 1: A certain soil sample has moisture content of 22%, a liquid limit of 15% and a plastic…
A: Moisture content=22% Liquid limit=15% Plastic limit=11%
Q: Laboratory test result showed that the void ratio of a saturated soil sample is 0.4. The specific…
A: Given e = 0.40 G= 2.60
Q: A soil sample is partially saturated. Its natural moisture content was found to be 22% and bulk…
A: Given data, Water content, w = 22% Bulk density = yb= 2gm/cc Specific gravity (G) = 2.65 Density of…
Q: A liquid limit test was performed on a soil sample. It was found out that the moisture content at 21…
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Q: If soil is dried beyond its shrinkage limit, it will show [1998] Select your answer A Large volume…
A: No Volume Change Explained below...
Q: soil sample has a water content of 18% and a wet unit weight of 118.5 lb/ft3. The specific gravity…
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Q: A dry soil sample weighs 68 g.. If the total volume of the sample is 40 mL and the specific gravity…
A: Given, Weight of solid (Ws)= 68gm Total volume of soil sample= V= 40mL Specific gravity= G = 2.65…
Q: a soil sample was determined to have a water content of 8% and a degree of saturation of 42%. After…
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Q: A sample of soil obtained from a construction site is found to have a wet weight of 29.4 lb. When…
A: It is required to determine the water content. Here, w is the water content, Wwet is the weight of…
Q: During test for water content determination on a soil sample by pycnometer. The following…
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Q: The laboratory test on a soil sample yields the following results: natural moisture content = 18%,…
A: given- water content=18%liquid limit=60%plastic limit=25%clay%=25%
Q: Data taken from Atterberg Limit test for a soil: Liquid Limit= 41.0 % Plastic Limit= 21.1% If the in…
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Q: SITUATION 1-A 1000 cc soil sample taken from the field weighs 1950 grams. Laboratory analysis shows…
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Q: A soil sample was determine in the laboratory to have a liquid limit of 41% and a plastic limit of…
A: The given data is: Liquid limit = 41% plastic limit = 21.1% WN=water content= 30%
Q: A Liquid Limit test was carried out on a sample of Clay with the following results: Number of taps…
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Q: A clay soil is found to have a liquid limit of 75 percent, a plastic limit of 45 percent, and a…
A: Given data: liquid limit Wl =75%plastic limit Wp= 45%Shrinkage limit Ws = 25%Total volume of soil at…
Q: a soil sample was determined to have a water content of 8% and a degree of saturation of 42%. After…
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Q: A soil sample with a grain specific gravity of 2.67 was filled in a 1000 mL container in the loosest…
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Q: A soil sample has a porosity of 41%, a moisture content of 15.2% and a specific gravity of 2.65.…
A: Given data- moisture content, w=15.2%porosity, n=41%specific gravity, G=2.65
Q: A soil borrow material in its natural state in the ground has a unit weight of 120 pcf. When a…
A: Given : Unit weight of soil borrow material in its natural state (γ) = 120 pcf…
Q: a soil sample was determined to have a water content of 8% and a degree of saturation of 42%. After…
A: Solution:-The given data ,Water content (w)=8%=0.08The degree of saturation(S)=42%=0.42Specific…
Q: SITUATION 3: A soil sample was determined in the laboratory to have a liquid limit of 41% and a…
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Q: A soil sample has a unit weight of 1.9 g/cc and w=12%. If Gs of solids is 2.65, determine the…
A: INTRODUCTION: Unit Weight : It is the ratio of weight of material accompanied to the unit volume of…
Q: Continued the above question: A soil sample is tested. Its minimum dry density=96 pcf and maximum…
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Q: An inorganic soil has a Liquid Limit of 55 and a Plastic Limit of 30. Using the plasticity chart…
A: The Liquid Limit of the soil is wL=55. The Plastic Limit of the soil is wp=30. The formula to…
Q: Example 2.21:The liquid limit and plastic limit of a soil are 50 % and 25 %, respectively When the…
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Q: The plastic limit of a soil is 35% and its plasticity index is 10%. When the soil is dried from its…
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Q: soil sample has a porosity late (a) voids ratio, (b) dry density, (c) unit weight if the soil
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Q: From a given inorganic soil, the following are known: Percentage passing No. 4 Sieve - 100…
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Q: A liquid limit test was performed on a soil sample. It was found out that the moisture content at 14…
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Q: A soil sample has a unit weight of 1.9 g/cc and w=12%. If Gs of solids is 2.65, determine the degree…
A: Determine the degree of saturation and porosity in percent.
Q: A sample of inorganic soil has the following grain size characteristics Size (mm) Percent passing…
A: Look at the % passing through No 200 i.e 0.075mm=34%<35% so Granular manterials
Q: A sample of clay soil taken from a construction site has a wet mass of 45.6 kg and a related inplace…
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Q: A sample of soil in its natural state has a volume of 1.396 m3 and weighs 18.662 kN. The sample was…
A: weight of soil in natural state, w=18.662KNVolume of soil, V =1.396m3After oven drying, weight of…
Q: The wet weight of a soil specimen is 207g. The dried weight of the specimen is 163g. If the volume…
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Q: Question 5 The results of the particle-size analysis of a soil are as follows: • Percent passing the…
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A liquid limits test carried out on a sample of inorganic soil taken from below the water table gave the following results:
Determine the liquid limit, plastic limit and plasticity index of this soil.
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- A traverse is being measure by theodolite and subtense bar. At one station, the theodolite axis is 1.36m above the ground mark and the horizontal angle subtended by a 2- meter subtense bar placed at the second station is 40'28". The subtense bar is 1.23m above the ground mark, and the vertical angle measured to it on the theodolite is +22°14'. Determine the horizontal distance between the two station marks. Your answer15. Using a theodolite, a subtended angle of 22'40" was read on a 2-m subtense bar. What is the horizontal distance in meter from the theodolite to the bar?A pre-engineering baseline was run down a very steep hill (see Rather than measure horizontally downhill with the steel tape, the surveyor measures the vertical angle with a theodolite and the slope distance with steel tape. The vertical angle is -21° 26’ turned to a point on a plumbed range pole that is 4.88 ft above the ground. The slope distance from the theodolite to the point on the range pole is 148.61 ft. The theodolite’s optical center is 4.66 ft above the upper baseline station at 110 + 71.25. If the elevation of the upper station is 318.71. what is the elevation of the lower station? What is the horizontal distance between the two stations?
- Please answer the problem attached image. Thank you very much. Use NSCP 2015. Hint: the answer Pr = 530 kNPc = 717.96 kNMrx (w/ amplification factor) = 20 kNmMry (w/ amplification factor) = 5.05 kNmMcx = 117.72 kNmMcy = 49.85 kNmInteraction Value = 0.98 < 1.0 safe - adequate sectionThe following subtended angles were read on a 2m long subtense bar using a theodolite. Compute for the values of D. a. at 0° 53'14" b. a=0°20'22" c. a, 0° 36'04"- The coordinates of point P (300,300) and B (500.550) m, the following observations were taken on two points A and Q with a theodolite: The external Angles BPQ = 144° 59' 48", BPA = 114° 0' 18", PBA = 133° 0' 42", PBQ = 98° 59' 30" Calculate the length of line AQ. A
- A 2-meter long sub tense bar was first set-up at A and subsequently at B, and the subtended angle to the bar, as read from a theodolite position somewhere along the middle of the line AB, were recorded as 33’15” and 38’34”. Determine the length of line AB.The readings obtained from a two-peg test carried out on an automatic level with a staff placed on two pegs A and B 50 m apart are: • With the level midway between A and B Staff reading at A = 1.283 m %3D Staff reading at B = 0.860 m With the level positioned 5 m from peg B on line AB extended Staff reading at B = 1.219 m %3D Staff reading at A = 1.612 m %3D %3D zontal reading that should be observed on the staff at A with the level in position 5 m from B. Calculate the collimation error of the level per 50 m sighting distance and the hori-Q2.The vertical angle reading measured from station A to station B,C,D are as shown in the Following Table: -Instrument station Face right 274 9.45' 10" 266 ° 32' 36" 262 ° 41' 18" station Face left 85 14 10" A C 93 ° 27' 14" 97 o 18'50" If the height of the theodolite instrument on the point A=1.5m and its elevation =30m..Calculate the elevations of points B, C, &D if the horizontal distance between points B,C,D, 50m ,100m 150m.respectively. CS Scanned with CamScanner
- 1)A traverse line is being measured by theodolite and subtense bar.At one station, the theodolite's horizontal axis is 1.54m above the ground mark and the angle subtended by a 2-m subtense bar placed at the next station is 4025". The subtense bar is 1.25m above the ground mark, and the vertical angle measured to it by the theodolite is (+)13°28.Determine: a)the horizontal distance from the theodolite at A to the subtense bar at B b)the vertical distance from the horizontal axis of the theodolite to the center of the bar c)the difference in elevation between the two ground stationsHi. Can you please answer this ASAP? Thank you! Determine the correcthorizontal distance AE when it was measured AB = 45m, BC= 38m, CD= 55m, DE =42.58, with difference of elevation per measurement as follows: 0.3m, 0.55m, 0.45m, 0.35m, measured with a 30-m tape under a steady pull of 6.5 kg at a mean temperature of 300C. If the tape used is of standard length at 200C under a pull of 5.5kg with a cross-sectional area of 0.025cm2, elastic modulus as 2.10x106kg/cm2, coefficient of thermal expansion to be 0.0000116/10C and weight of tape is 0.5kg.3. A 2-meter long subtense bar was first set up at A and subsequently at B, and the subtended a to the bar, as read from a theodolite positioned somewhere along the middle of line AB, were recorded as 45'30" and 56'11", respectively. Determine the line AB. 4. If the scaled horizontal distance between points A and b is 433.,50m and the elevation of A ar