A load of weight 500 N is suspended by cable AB and two cords which are attached to blocks of weights W and F as shown in the figure (1 Determine tension in the cable AB and the value of weight W. FN=87N F...... N. 500 mm 800 mm 600 mm 600 mm 400 mm W O A 500 N 300 mm B FN
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- By what distance h does the cage shown in the figure move downward when the weight W is placed inside it? (See the figure.) Consider only the effects of the stretching of the cable, which has axial rigidity EA = 10,700 kN. The pulley at A has a diameter da= 300 mm and the pulley at B has a diameter dB= 150 mm. Also, the distance L1= 4.6 m, the distance L2=10.5 m, and the weight W = 22 kN. Note: When calculating the length of the cable. include the parts of the cable that go around the pulley sat A and B..15 A hitch-mounted bicycle rack is designed to carry up to four 30-lb bikes mounted on and strapped to two arms Gil (sec bike loads in the figure part a) The rack is attached to the vehicle at A and is assumed to be like a cant silkier beam A BCDGII (figure part b) The light of fixed segment AB is U = 10 lb. centered 9 in. from A (see figure part b) and the rest of the rack highs W2 = 40 lb. centered 19 in. from A. Segment ABCDG is a steel tube o(2 X 2 in. with a thickness I = 118 in. Segment BCDGII pivots about a bolt at B with a diameter d1 = 0.25 in. to allow access to the rear of the vehicle without removing the hitch rack. When in use, the rack is secured in an upright posit ion by a pin C(diameter o( pin d, = 5116 in.) (see phoo and figure part C). The of returning effect of the bikes on the rack is resisted by a force couple F h at BC. (a) Find the support reactions at A for the fully loaded rack. (b) Find forces in the bolt at B and the pin at C. (c) Find average shear stresses in both the bolt at Band the pin at C. (d) Find average bearing stresses o, in the bolt at B and the pin at C.Determine the tensions T1 and T2 in the strings required to maintain equilibrium for the suspended object weighs W = 48.7N shown in the figure. Take, α = 29.4° & β = 47.5°. a) The value of θ1 (Degree) = b) The value of θ2 (Degree) = c) The value of θ3 (Degree) = d) The value of Tension, T1 (N) = e) The value of Tension, T2 (N) =
- A horizontal board weighing Wb = 600 N is hinged to a vertical wall. A personweighing Wp = 400 N stands at the end of the board 5 m from the wall. A rope is attached to theboard at a point 3 m from the wall and makes an angle of θ = 40° with theboard. Determine the tension (T) in the ropeWhat would be the maximum weight W of the block, shown in the following figure, so that the tension developed in any cable does not exceed 100 NTwo gondolas on a ski lift are locked in the postion show in the figure while repairs are being made elsewhere.The distance between support towers is L = LOO ft.The length of each cable segement under gondolas weighing WB= 450 lb and Wc=650 lb are DAB=12 ft, DBC=70 a , and DCB=20 ft . The cable sag at B is AB = 3.9 ft and that C is A = 7.1 ft.THe effective cross-sectional area of the cables is Ae=0.12 in". (a) Find the tension force in each segment; neglect the mass of the cable. (b) Find the average stress(σ) in each cable segment.
- In the figure shown, there is an armature that is supported by a cable and a simple support at B. In addition, this armature rests on a spring with a constant as indicated in the figure. By applying the loads shown at points H and L, the spring is compressed by 10 cm.Determine:a) The reactions in the support at B and the tension in the cable AD.b) The force in the element I - K by the method of sections (determine if the element is in tension or compression)A frame structure, as shown in the following diagram, is given. Calculate: (a) Reaction forces at each support (b) Forces acting on members AB, BD, and DE using the Section Method And it is known that P = 700 kN, Q = 300 kN, a = 10 m, b = 8 m, and c = 6mIn the figure the boom derrick supports a suspended 15-kip load . The booms BC and DE are each 20 ft long. The distances are a = 15 ft and b = 2 ft, and the angle θ= 30 degrees . The angle between BE and BC in 77.4 degrees . Determine the tension in cable AB and the reactions at the pin supports and D.
- The simplest truss consists of two rods and is loaded by the block. Given: block weight Q = 9,4 kN. Angle α = 31 degrees. Find: the algebraic (positive or negative) value (in kN) of normal force N1 in the rod 1, considering that N1>0 for tension and N1<0 for compression.Shown in the following figure is a foldable table loaded by weight “W”. The contact points, B, D, and E are frictionless. 1. Find the safest load W if the allowable tensile force in the cable is 1800 N. a. 600Nb. 180 Nc. 482Nd. 630N2. If W = 1500 N, find the reaction at D. a. 500 Nb. 1000 Nc. 800 Nd. 1200 N3. If W = 1500 N, find the reaction at B.a. 500 Nb. 1000 Nc. 800 Nd. 1200 NMember AB (helical spring) and Member AC (axial rod) are carrying a weight at point A. Member AB has the following properties: R = 90 mm, n =4 turns, G = 70 GPa, d = 30 mm, and allow = 105 MPa while Member AC has the following properties: L = 2 , A = 500 mm2, E = 200 GPa, and allow = 30 MPa. Determine the maximum safe value of W (in N). Use simplified formula for the helical spring.