A long jumper (above Fig.) leaves the ground at an angle of 20° to the horizontal and at a speed of 11 m/s. (a) How long does it take for him to reach maximum height? tmax= (b) What is the maximum height? ymax= (c) How far does he jump? R= (d) Use Equation vž = vy – 2gAy to find the maximum height he reaches. ymax = %3D -

A long jumper (above Fig.) leaves the ground at an angle of 20° to the horizontal and at a speed of 11 m/s. (a) How long does it take for him to reach maximum height? tmax= (b) What is the maximum height? ymax= (c) How far does he jump? R= (d) Use Equation vž = vy – 2gAy to find the maximum height he reaches. ymax = %3D -

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Description: نقطتان )2(Q2-aQ2:A long jumper (above Fig.) leaves the ground at an angle of 20° to the horizontal and ata speed of 11 m/s.(a) How long does it take for him to reach maximum height? tmax=(b) What is the maximum height? ymax=(c) How far does he jump?

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter3: Motion In Two Dimensions

Section: Chapter Questions

Problem 7OQ: A projectile is launched on the Earth with a certain initial velocity and moves without air...

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