A member is formed by connecting two steel bars shown below. Assuming that the bars are prevented frombuckling sideways, calculate the magnitude force "P" that will cause the total length of the member todecrease 0.24 mm the values of elastic modulus for steel is 221 MPa. Take H1 = 4 cm, H2is 2 x 2 cm and bottom bar (Q) is 6 x 6 cm. Also, determine the stress-induced in each section of thebar.= 9 cm, top bar (R)IPSolution:R cm x RCmSteel bari) Magnitude Force, P =H1 cmii) Stress-induced in the top bar =Q cm x Q cmSteel barH2 cmiii) Stress-induced in the bottom bar =

Given data: The height of the upper beam is H1=4 cm=40 mm The height of the bottom beam is H2=9…

A member is formed by connecting two steel bars shown below. Assuming that the bars are prevented from buckling sideways, calculate the magnitude force "P" that will cause the total length of the member to decrease 0.24 mm the values of elastic modulus for steel is 221 MPa. Take H1 = 4 cm, H2 = 9 cm, top bar (R) is 2 x 2 cm and bottom bar (Q) is 6 x 6 cm. Also, determine the stress-induced in each section of the bar. %3D Solution: R Cm X R Cm Steel bar i) Magnitude Force, P = H1 cm ii) Stress-induced in the top bar = Q cm x Qcm Steel bar H2 cm iii) Stress-induced in the bottom bar =

A member is formed by connecting two steel bars shown below. Assuming that the bars are prevented from buckling sideways, calculate the magnitude force "P" that will cause the total length of the member to decrease 0.24 mm the values of elastic modulus for steel is 221 MPa. Take H1 = 4 cm, H2 = 9 cm, top bar (R) is 2 x 2 cm and bottom bar (Q) is 6 x 6 cm. Also, determine the stress-induced in each section of the bar. %3D Solution: R Cm X R Cm Steel bar i) Magnitude Force, P = H1 cm ii) Stress-induced in the top bar = Q cm x Qcm Steel bar H2 cm iii) Stress-induced in the bottom bar =

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter8: Applications Of Plane Stress (pressure Vessels, Beams, And Combined Loadings)

Section: Chapter Questions

Problem 8.2.6P: A rubber ball (sec figure) is inflated to a pressure of 65 kPa. At that pressure, the diameter of...

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