A member is formed by connecting two steel bars shown below. Assuming that the bars are prevented from buckling sideways, calculate the magnitude force "P" that will cause the total length of the member to decrease 0.71 mm the values of elastic modulus for steel is 221 MPa. Take H1 = 5 cm, H2 = 11 cm, top bar (R) is 3 x 3 cm and bottom bar (Q) is 5 x 5 cm. Also, determine the stress-induced in each section of the bar. Solution: R CM X R Cm i) Magnitude Force, P = Steel bar H1 cm ii) Stress-induced in the top bar = Q cm x Qcm Šteel bar H2 cm iii) Stress-induced in the bottom bar =

A member is formed by connecting two steel bars shown below. Assuming that the bars are prevented from buckling sideways, calculate the magnitude force "P" that will cause the total length of the member to decrease 0.71 mm the values of elastic modulus for steel is 221 MPa. Take H1 = 5 cm, H2 = 11 cm, top bar (R) is 3 x 3 cm and bottom bar (Q) is 5 x 5 cm. Also, determine the stress-induced in each section of the bar. Solution: R CM X R Cm i) Magnitude Force, P = Steel bar H1 cm ii) Stress-induced in the top bar = Q cm x Qcm Šteel bar H2 cm iii) Stress-induced in the bottom bar =

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter3: Torsion

Section: Chapter Questions

Problem 3.4.17P: .17 A mountain-bike rider going uphill applies torque T = Fd(F = l5lb, d = 4 in.) to the end of the...

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