A motorcyclist heads 267 m/s, 35.76° N of W and then it changes its direction heading 46 m/s West before it reaches its destination. Calculate the following: I.   value of summation and direction of Vx II.   value of summation and direction of Vy and III.   The value of resultant vector of velocity and the angle formed A.   262.66 m/s West    ;   156.03 m/s North   ;   305.51 m/s, 30.71 N of W B.    245.45 m/s North   ;   145.02 m/s West   ;   385.09 m/s, 39.09 W of N C.    156.23 m/s West  ;   58.74 m/s North      ;   166.91 m/s, 28.54 N of W D.    178.34 m/s North   ;   65.36 m/s West     ;   189.94 m/s, 19.34 W of N

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section1.10: Cornoonentsofavector
Problem 1.2QQ: Figure 1.19 shows two vectors lying in the xy-plane. Determine the signs of the x- and y-components...
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16-20 A motorcyclist heads 267 m/s, 35.76° N of W and then it changes its direction heading 46 m/s West before it reaches its destination. Calculate the following:

I.   value of summation and direction of Vx

II.   value of summation and direction of Vy and

III.   The value of resultant vector of velocity and the angle formed

A.   262.66 m/s West    ;   156.03 m/s North   ;   305.51 m/s, 30.71 N of W

B.    245.45 m/s North   ;   145.02 m/s West   ;   385.09 m/s, 39.09 W of N

C.    156.23 m/s West  ;   58.74 m/s North      ;   166.91 m/s, 28.54 N of W

D.    178.34 m/s North   ;   65.36 m/s West     ;   189.94 m/s, 19.34 W of N

 

21-25 A body is projected with an initial velocity of 25.5 m/s at 30° below the horizontal. Find a.) time of flight b.)the maximum height attained by the body, and  c.) range

A. Time of flight = 1.3s ; Maximum height = 7.7m ; Range = 55m

B. Time of flight = 2.5s ; Maximum height = 8.7m ; Range = 60m

C. Time of flight = 1.1s ; Maximum height = 6.9m ; Range = 45m

D. Time of flight = 2.3s ; Maximum height = 9.7m ; Range = 65m

16-20 A motorcyclist heads 267 m/s, 35.76° N of W and then it changes its direction
heading 46 m/s West before it reaches its destination. Calculate the fallowing:
1. value of summation and direction of Vx
II. value of summation and direction of Vy and
II. The value of resultant vector of velocity and the angle formed
A. 262,66 m/s West ; 156.03 m/s North ; 305.51 m/s, 30.71 N of W
B. 245.45 m/s North ; 145.02 m/s West ; 385.09 m/s, 39.09 W of N
C. 156.23 m/s West ; 58.74 m/s North
; 166.91 m/s, 28.54 N of W
D. 178.34 m/s North ; 65.36 m/s West ; 189.94 m/s, 19.34 W of N
21-25 A body is projected with an initial velocity of 25.5 m/s at 30° below the
horizontal. Find a.) time of flight b.)the maximum height attained by the body, and c) range
A. Time of flight = 1.35; Maximum height = 7.7m; Range = 55m
B. Time of flight = 2,5s; Maximum height = 8.7m; Range = 60m
C. Time of flight = 1.1s; Maximum height= 6.9m; Range = 45m
D. Time of flight = 2.35; Maximum height = 9.7m ; Range = 65m
26-30 A woman pushes on a 2.0kg cart with a force of 300N. The cart moves at a speed
of 5.0m/s with a horizontal distance of 3.0m in just 4.015. Calculate the following
I.
Work
I.
Energy
I.
Power
A Work = 1000) ; Energy = 30); Power = 230.68 W
%3D
B. Work = 890) ; Energy = 45) ; Power = 325.47 W
%3D
%3D
C. Work =900) ; Energy = 25) ; Power = 224.44 W
%3D
D. Work = 729); Energy = 56) ; Power = 429.27 W
%3!
Transcribed Image Text:16-20 A motorcyclist heads 267 m/s, 35.76° N of W and then it changes its direction heading 46 m/s West before it reaches its destination. Calculate the fallowing: 1. value of summation and direction of Vx II. value of summation and direction of Vy and II. The value of resultant vector of velocity and the angle formed A. 262,66 m/s West ; 156.03 m/s North ; 305.51 m/s, 30.71 N of W B. 245.45 m/s North ; 145.02 m/s West ; 385.09 m/s, 39.09 W of N C. 156.23 m/s West ; 58.74 m/s North ; 166.91 m/s, 28.54 N of W D. 178.34 m/s North ; 65.36 m/s West ; 189.94 m/s, 19.34 W of N 21-25 A body is projected with an initial velocity of 25.5 m/s at 30° below the horizontal. Find a.) time of flight b.)the maximum height attained by the body, and c) range A. Time of flight = 1.35; Maximum height = 7.7m; Range = 55m B. Time of flight = 2,5s; Maximum height = 8.7m; Range = 60m C. Time of flight = 1.1s; Maximum height= 6.9m; Range = 45m D. Time of flight = 2.35; Maximum height = 9.7m ; Range = 65m 26-30 A woman pushes on a 2.0kg cart with a force of 300N. The cart moves at a speed of 5.0m/s with a horizontal distance of 3.0m in just 4.015. Calculate the following I. Work I. Energy I. Power A Work = 1000) ; Energy = 30); Power = 230.68 W %3D B. Work = 890) ; Energy = 45) ; Power = 325.47 W %3D %3D C. Work =900) ; Energy = 25) ; Power = 224.44 W %3D D. Work = 729); Energy = 56) ; Power = 429.27 W %3!
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