(a) Н—С—С—С—С—СEN (b) Н—О—с--с—о—н (с) Н—N—N—H

Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter1: Matter, Energy, And Measurement
Section: Chapter Questions
Problem 1.86P: 1-86 The specific heats of some elements at 25oC are as follows: aluminum = 0.215 cal/g · oC; carbon...
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Predict the molecular geometry of each of the following
molecules:

(a) Н—С—С—С—С—СEN
(b) Н—О—с--с—о—н
(с) Н—N—N—H
Transcribed Image Text:(a) Н—С—С—С—С—СEN (b) Н—О—с--с—о—н (с) Н—N—N—H
Expert Solution
Step 1

(a)Given molecule is

Chemistry homework question answer, step 1, image 1

The shape of the molecule is determined by the geometry possess by the carbon atom present in the molecule.

From the given structure, it is clear that each carbon (C) atom has two electron domains which are bonding. Therefore, the geometry of electron domain is linear having sp hybridization. Hence, the molecule has linear shape.

Step 2

(b)Given molecule is

Chemistry homework question answer, step 2, image 1

The shape of the molecule is determined by the geometry possess by the carbon atom present in the molecule.

From the given structure, it is clear that each carbon (C) atom at the center of the molecule has three electron domains which are bonding. Therefore, the geometry of electron domain is trigonal planar having sp2 hybridization. The carbon and oxygen atoms are arranged in the plane and H atoms are free to rotate in and out of the plane. Hence, the molecule has trigonal planar shape.

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