A parallel-plate capacitor is made from two square metal plates spaced 1 mm apart. 1. If the plates measure 5 cm on each, what is its capacitance? 2. If this capacitor is charged with a 9-volt battery, how much charge does it accumulate?

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A: We can see the graph in question

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A: The voltage source is V=295 V. The capacitance is C=126μF=126×10-6 F  

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A: Potential difference (V) = 4.50 volts Current through the wire (I) = 17.6 A   

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A: We know thatC=Q∆VHereC=CapacitanceQ=charge∆V=Potential difference

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Combination of Capacitors

The connection of capacitors can be established in a circuit in two ways.