A particle at rest leaves the origin with its velocity increasing with time according to v(t) = 3.2t m/s. At 5.0s, the particle’s velocity starts decreasing according to [16.0 – 1.5(t – 5.0)] m/s. This decrease continues until t = 11.0s, after which the particle’s velocity remains constant at 7.0 m/s. (a) What is the acceleration of the particle as a function of time? (b) What is the position of the particle at t = 2.0s, t = 7.0s, and t = 12.0s?

A particle at rest leaves the origin with its velocity increasing with time according to v(t) = 3.2t m/s. At 5.0s, the particle’s velocity starts decreasing according to [16.0 – 1.5(t – 5.0)] m/s. This decrease continues until t = 11.0s, after which the particle’s velocity remains constant at 7.0 m/s. (a) What is the acceleration of the particle as a function of time? (b) What is the position of the particle at t = 2.0s, t = 7.0s, and t = 12.0s?

Classical Dynamics of Particles and Systems

5th Edition

ISBN:9780534408961

Author:Stephen T. Thornton, Jerry B. Marion

Publisher:Stephen T. Thornton, Jerry B. Marion

Chapter2: Newtonian Mechanics-single Particle

Section: Chapter Questions

Problem 2.30P: A student drops a water-filled balloon from the roof of the tallest building in town trying to hit...

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