A particle is acted on by a conservative force, F= (-Ax + Bx)i N, where A and B are constants, and x is in meters. (For your answers, use the following as necessary: A, B, and x.) (a) Determine the potential energy function (in 3) for F, where U = 0 at x= 0. Ax U(x) = Use the equation relating the change in potential energy to the conservative force acting on the particle: AU =- F, dx, and note that U,- 0.) (b) Determine the change in potential energy (in ) as the particle moves from x= 2.30 m to x= 4.00 m. AU - 5.3554 - 657.99B (c) Determine the change in kinetic energy (in 3) as the particle moves from x- 2.30 m to x = 4.00 m. AK- 5.355A + 657.99B x Think about the particle as a system. Then, the change in kinetic energy is the work done by the force on the particle: W- AK. Then, for the entire system, this work pegative of the chanoe in notential energy of the svetem internal work and equal to the

University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter8: Potential Energy And Conservation Of Energy
Section: Chapter Questions
Problem 50P: A particle of mass 0.50 kg moves along the x -axis with a potential energy whose dependence on x is...
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A particle is acted on by a conservative force, F = (-Ax + Bx)Î N, where A and B are constants, and x is in meters. (For your answers, use the following as necessary: A, B, and x.)
(a) Determine the potential energy function (in J) for F, where U = 0 at x = 0.
Ax
Bx
U(x) =
Use the equation relating the change in potential energy to the conservative force acting on the particle: AU = -
F, dx, and note that U, = 0. J
(b) Determine the change in potential energy (in J) as the particle moves from x = 2.30 m to x = 4.00 m.
AU = 5.355A – 657.99B
(c) Determine the change in kinetic energy (in J) as the particle moves from x = 2.30 m to x = 4.00 m.
AK = 5.3554 + 657.99B x
Think about the particle as a system. Then, the change in kinetic energy is the work done by the force on the particle: W = AK. Then, for the entire system, this work is internal work and equal to the
negative of the change in potential energy of the system. J
Transcribed Image Text:A particle is acted on by a conservative force, F = (-Ax + Bx)Î N, where A and B are constants, and x is in meters. (For your answers, use the following as necessary: A, B, and x.) (a) Determine the potential energy function (in J) for F, where U = 0 at x = 0. Ax Bx U(x) = Use the equation relating the change in potential energy to the conservative force acting on the particle: AU = - F, dx, and note that U, = 0. J (b) Determine the change in potential energy (in J) as the particle moves from x = 2.30 m to x = 4.00 m. AU = 5.355A – 657.99B (c) Determine the change in kinetic energy (in J) as the particle moves from x = 2.30 m to x = 4.00 m. AK = 5.3554 + 657.99B x Think about the particle as a system. Then, the change in kinetic energy is the work done by the force on the particle: W = AK. Then, for the entire system, this work is internal work and equal to the negative of the change in potential energy of the system. J
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