A particle moves through an xyz coordinate system while a force acts on the particle. When the particle has the position vector 7 = (2.00 m) î - (3.00 m)ĵ + (2.00 m) k, the force is F = F,î + (7.00 N) ĵ - (6.00 N) k, and the corresponding torque about the origin is 7 = (4.00 N-m) î + (10.0 N-m)ĵ + (11.0 N-m) k. Determine F. Number Units

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