Problem 9: The rotational inertia of a collapsing spinning star drops from an initial value I= 9 x 109 kg m² to a value of I, = 3 x 109 kg m². (a) Ratio of final rotational kinetic energy (KE,) to the initial rotational KE, is (b) What would that ratio be if I/I=1/4?.

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
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Chapter10: Rotational Motion
Section: Chapter Questions
Problem 18P: Rigid rods of negligible mass lying along the y axis connect three particles (Fig. P10.18). The...
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Problem 9: The rotational inertia of a collapsing spinning star drops from an initial value Ii= 9 x 10^99 kg m2 to a value of If = 3 x 1099 kg m2.

(a) Ratio of final rotational kinetic energy (KEf) to the initial rotational KEi is ________

(b) What would that ratio be if If/Ii=1/4? ________

Problem 9: The rotational inertia of a collapsing spinning
star drops from an initial value I= 9 x 109 kg m² to a value
of I, = 3 x 109 kg m².
(a) Ratio of final rotational kinetic energy (KE,) to the
initial rotational KE, is
(b) What would that ratio be if I/I,=1/4?_
Transcribed Image Text:Problem 9: The rotational inertia of a collapsing spinning star drops from an initial value I= 9 x 109 kg m² to a value of I, = 3 x 109 kg m². (a) Ratio of final rotational kinetic energy (KE,) to the initial rotational KE, is (b) What would that ratio be if I/I,=1/4?_
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